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2 years ago

(help) Miller’s Farm had apples on sale for $1.78 a pound. Maria spent $15.21 on apples. How many pounds did she buy?

Mathematics

1 answer:

jolli1 [7]2 years ago

5 0

Answer:

8.5 pounds

Step-by-step explanation:

$ 1.78 - 1 pound

$ 15.21 - 15.21/1.78

= 8.5

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Help me asap pleaseeeeeeeeeeeeeeeeeee !!

grin007 [14]

Answer: rrxckz if i knew the answer i would give it to you.

8 0

3 years ago

Suppose that E and F are two events and that N(E and F)=300 and N(E)=730. What is P(F|E)?

marin [14]

Answer:

$\displaystyle\frac{30}{73}$

Step-by-step explanation:

The formula of conditional probability is:

$\displaystyle P(F|E)=\frac{P(E \cap F)}{P(E)}$

And if we called N(U) the total number of possible outcomes, then remember by definition of probability:

$\displaystyle P(E \cap F)=\frac{N(E \cap F)}{N(U)}\\\displaystyle P(E)=\frac{N(E)}{N(U)}$

Then plugging them into the formula of conditional probability we get:

$\displaystyle P(F|E)=\frac{\frac{N(E \cap F)}{N(U)}}{\frac{N(E)}{N(U)}}$

Then we simplify and we get:

$\displaystyle P(F|E)=\frac{N(E \cap F)}{N(E)}$

We just plug the given info and we get:

$\displaystyle P(F|E)=\frac{300}{730}=\frac{30}{70}$

3 0

3 years ago

Use the graphing calculator to graph the system.

Gekata [30.6K]

The solutions to the system are -11.3 and 11.3.

The length of one leg of the sun shade is 11.3 feet.

Steps:

graph y=1/2 x^2

graph y=64

zoom out.

find the points of intersection.

done.

7 0

3 years ago

Read 2 more answers

Tbh I'm just too lazy to actually do this and my head hurts from the rest of my school work so I'm just asking it on here -2/5 +

Leto [7]

Answer:

1/10

Step-by-step explanation:

-2/5 + 1/2

-4/10 + 5/10

-4 + 5/10

= 1/10

Hope this helps!

6 0

4 years ago

Read 2 more answers

PLEASE PLEASE HELP! Find the measure of APB^.

Whitepunk [10]

Answer:

65°

Step-by-step explanation:

Radii CA and CB are perpendicular to tangent lines AT and BT, so

$\angle CAT=\angle CBT=90^{\circ}$

Since angle BAT is equal to 65°, angle CAB has measure

$\angle CAB=90^{\circ}-65^{\circ}=25^{\circ}.$

Consider triangle ACB. This triangle is isosceles, because CA=CB as radii of the circle. Two angles adjacent to the base are congruent, thus

$\angle CBA=\angle CAB=25^{\circ}$

The sum of the measures of all interior angles in triangle is always 180°, so

$\angle CAB+\angle CBA+\angle ACB=180^{\circ}\\ \\25^{\circ}+25^{\circ}+\angle ACB=180^{\circ}\\ \\\angle ACB=130^{\circ}$

Angle ACB is central angle subtended on the minor arc AB, angle APB is inscribed angle subtended on the same minor arc AB. The measure of inscribed angle is half the measure of central angle subtended on the same arc, so

$x=\angle APB=\dfrac{1}{2}\cdot 130^{\circ}=65^{\circ}$

8 0

3 years ago