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Free_Kalibri [48]
3 years ago
13

Write the trigonometry ratio for the triangle below.

Mathematics
2 answers:
faltersainse [42]3 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

(a)

cosB = \frac{adjacent}{hypotenuse} = \frac{BC}{AB} = \frac{a}{c}

(b)

tanA = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{a}{b}

(c)

sinB = \frac{opposite}{hypotenuse} = \frac{AC}{AB} = \frac{b}{c}

Ludmilka [50]3 years ago
5 0

Answer:

cos B = a/c

tan A = a/b

sin B = b/c.

Step-by-step explanation:

Sin = opposite / hypotenuse

cos = adjacent/ hypotenuse

tan = opposite/adjacent.

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Find the exact circumference. <br><br> r = 6 mm, C = ?
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C=2 \pi r \\ C=2 \pi 6 \\ C=12 \pi
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2 years ago
I need the equation and the answer and how to do it, thank you&lt;3
vazorg [7]

Answer:

19=5+(j times 2/3) j=21

Step-by-step explanation:

While reading out the equation, you understand that Hannah's 19 Jolly Ranchers is what the equation is being set to. 5 more means +5. 2/3 of J can be written as (2/3 times J). You can solve for J by setting the equation to J.

3 0
3 years ago
A foreign student club lists as its members 2 Canadians, 3 Japanese, 5 Italians, and 2 Germans. If a committee of 4 is selected
Fittoniya [83]

Answer:

(a) The probability that the members of the committee are chosen from all nationalities =\frac{4}{33}  =0.1212.

(b)The probability that all nationalities except Italian are represent is 0.04848.

Step-by-step explanation:

Hypergeometric Distribution:

Let x_1, x_2, x_3 and x_4 be four given positive integers and let x_1+x_2+x_3+x_4= N.

A random variable X is said to have hypergeometric distribution with parameter x_1, x_2, x_3 , x_4  and n.

The probability mass function

f(x_1,x_2.x_3,x_4;a_1,a_2,a_3,a_4;N,n)=\frac{\left(\begin{array}{c}x_1\\a_1\end{array}\right)\left(\begin{array}{c}x_2\\a_2\end{array}\right) \left(\begin{array}{c}x_3\\a_3\end{array}\right) \left(\begin{array}{c}x_4\\a_4\end{array}\right)  }{\left(\begin{array}{c}N\\n\end{array}\right) }

Here a_1+a_2+a_3+a_4=n

{\left(\begin{array}{c}x_1\\a_1\end{array}\right)=^{x_1}C_{a_1}= \frac{x_1!}{a_1!(x_1-a_1)!}

Given that, a foreign club is made of  2 Canadian  members, 3 Japanese  members, 5 Italian  members and 2 Germans  members.

x_1=2, x_2=3, x_3 =5 and x_4=2.

A committee is made of 4 member.

N=4

(a)

We need to find out the probability that the members of the committee are chosen from all nationalities.

a_1=1, a_2=1,a_3=1 , a_4=1, n=4

The required probability is

=\frac{\left(\begin{array}{c}2\\1\end{array}\right)\left(\begin{array}{c}3\\1\end{array}\right) \left(\begin{array}{c}5\\1\end{array}\right) \left(\begin{array}{c}2\\1\end{array}\right)  }{\left(\begin{array}{c}12\\4\end{array}\right) }

=\frac{2\times 3\times 5\times 2}{495}

=\frac{4}{33}

=0.1212

(b)

Now we find out the probability that all nationalities except Italian.

So, we need to find out,

P(a_1=2,a_2=1,a_3=0,a_4=1)+P(a_1=1,a_2=2,a_3=0,a_4=1)+P(a_1=1,a_2=1,a_3=0,a_4=2)

=\frac{\left(\begin{array}{c}2\\2\end{array}\right)\left(\begin{array}{c}3\\1\end{array}\right) \left(\begin{array}{c}5\\0\end{array}\right) \left(\begin{array}{c}2\\1\end{array}\right)  }{\left(\begin{array}{c}12\\4\end{array}\right) }+\frac{\left(\begin{array}{c}2\\1\end{array}\right)\left(\begin{array}{c}3\\2\end{array}\right) \left(\begin{array}{c}5\\0\end{array}\right) \left(\begin{array}{c}2\\1\end{array}\right)  }{\left(\begin{array}{c}12\\4\end{array}\right) }+\frac{\left(\begin{array}{c}2\\1\end{array}\right)\left(\begin{array}{c}3\\1\end{array}\right) \left(\begin{array}{c}5\\0\end{array}\right) \left(\begin{array}{c}2\\2\end{array}\right)  }{\left(\begin{array}{c}12\\4\end{array}\right) }

=\frac{1\times 3\times 1\times 2}{495}+\frac{2\times 3\times 1\times 2}{495}+\frac{2\times 3\times 1\times 1}{495}

=\frac{6+12+6}{495}

=\frac{8}{165}

=0.04848

The probability that all nationalities except Italian are represent is 0.04848.

6 0
3 years ago
Last question! I need help with showing my work! I already have the answer in the attached image below, thanks!
Rainbow [258]

Answer:

see explanation

Step-by-step explanation:

Given

\sqrt{\frac{4x^2}{3y} }

= \frac{\sqrt{4x^2} }{\sqrt{3y} }

= \frac{2x}{\sqrt{3y} }

Rationalise the denominator by multiplying the numerator/ denominator by \sqrt{3y}

Note that \sqrt{a} × \sqrt{a} = a

= \frac{2x}{\sqrt{3y} } × \frac{\sqrt{3y} }{\sqrt{3y} }

= \frac{2x\sqrt{3y} }{3y}

5 0
3 years ago
Which graph represents y=x-5?​
elena-s [515]
Can uu show the rest of the graph??????
3 0
2 years ago
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