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Anestetic [448]
3 years ago
14

Ben bought 2 shirts for $16 each, 3 pairs of socks for $2.50 a pair, and a pair of jeans for $37.75. If the sales tax rate is 6.

5%, how much did he pay for his items?
Mathematics
1 answer:
user100 [1]3 years ago
6 0

Answer:

Total amount pay by Ben = $82.27 (Approx.)

Step-by-step explanation:

Given:

2 Shirts = $16 each

3 pairs of socks = $2.50 each

1 pair of jeans = $37.75 each

Sales tax = 6.5%

Find:

Total amount pay by Ben

Computation:

Total amount for shirts = 2 x 16

Total amount for shirts = $32

Total amount for socks = 3 x 2.50

Total amount for shirts = $7.50

Total amount before tax = $32 + $7.50 + $37.75

Total amount before tax = $77.25

Total amount pay by Ben = Total amount before tax[1+tax]

Total amount pay by Ben = 77.25[1+6.5%]

Total amount pay by Ben = $82.27 (Approx.)

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3 years ago
5x + 2 (x+7) =14x - 7
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The answer is x=-23/21
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3 years ago
Suppose I ask you to pick any four cards at random from a deck of 52, without replacement, and bet you one dollar that at least
Tatiana [17]

Answer:

a) No, because you have only 33.8% of chances of winning the bet.

b) No, because you have only 44.7% of chances of winning the bet.

Step-by-step explanation:

a) Of the total amount of cards (n=52 cards) there are 12 face cards (3 face cards: Jack, Queen, or King for everyone of the 4 suits: clubs, diamonds, hearts and spades).

The probabiility of losing this bet is the sum of:

- The probability of having a face card in the first turn

- The probability of having a face card in the second turn, having a non-face card in the first turn.

- The probability of having a face card in the third turn, having a non-face card in the previous turns.

- The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

<u><em>1) The probability of having a face card in the first turn</em></u>

In this case, the chances are 12 in 52:

P_1=P(face\, card)=12/52=0.231

<u><em>2) The probability of having a face card in the second turn, having a non-face card in the first turn.</em></u>

In this case, first we have to get a non-face card (there are 40 in the dech of 52), and then, with the rest of the cards (there are 51 left now), getting a face card:

P_2=P(non\,face\,card)*P(face\,card)=(40/52)*(12/51)=0.769*0.235=0.181

<u><em>3) The probability of having a face card in the third turn, having a non-face card in the first and second turn.</em></u>

In this case, first we have to get two consecutive non-face card, and then, with the rest of the cards, getting a face card:

P_3=(40/52)*(39/51)*(12/50)\\\\P_3=0.769*0.765*0.240=0.141

<u><em>4) The probability of having a face card in the fourth turn, having a non-face card in the previous turns.</em></u>

In this case, first we have to get three consecutive non-face card, and then, with the rest of the cards, getting a face card:

P_4=(40/52)*(39/51)*(38/50)*(12/49)\\\\P_4=0.769*0.765*0.76*0.245=0.109

With these four probabilities we can calculate the probability of losing this bet:

P=P_1+P_2+P_3+P_4=0.231+0.181+0.141+0.109=0.662

The probability of losing is 66.2%, which is the same as saying you have (1-0.662)=0.338 or 33.8% of winning chances. Losing is more probable than winning, so you should not take the bet.

b) If the bet involves 3 cards, the only difference with a) is that there is no probability of getting the face card in the fourth turn.

We can calculate the probability of losing as the sum of the first probabilities already calculated:

P=P_1+P_2+P_3=0.231+0.181+0.141=0.553

There is 55.3% of losing (or 44.7% of winning), so it is still not convenient to bet.

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4 years ago
How long will it take Carlos to walk 16 miles if he is walking 4 mph?
qwelly [4]
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3 years ago
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1 dimes are worth 10 cents.

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Put in a fraction with the denominator given.

60/100

Reduce the fraction.

60/100

30/50

15/25

3/5

Best of Luck!

7 0
3 years ago
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