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2 answers:
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Answer:
Therefore, the error is 52-50.27=1.73.
Step-by-step explanation:
We know that Sid used geometry software to draw a circle of a radius 4 units on a fgrid. He estimated the area of the circle by ciunting the squares that were mostly inside the circle and got an answer of 52 sq units.
We use the formula:
Therefore, the error is 52-50.27=1.73.
the length of a spool of ribbon with a z-score of 0.7 is 92.3 cm
<u>Step-by-step explanation:</u>
Here we have , The lengths of spools of ribbon are normally distributed with a mean of 91.4 centimeters and a standard deviation of 1.3 centimeters. What is the length of a spool of ribbon with a z-score of 0.7 . Let's find out:
According to Question we have following parameters as :
X = the length of a spool of ribbon
Mean(x) = 91.4 cm
standard deviation(y) = 1.3 cm
Z = 0.7
We know that Z score is given by :
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Therefore , the length of a spool of ribbon with a z-score of 0.7 is 92.3 cm