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9966 [12]
3 years ago
14

Geometry khan Academy

Mathematics
1 answer:
MrRissso [65]3 years ago
4 0

Answer:

.............................

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On a coordinate plane, a line is drawn from point A to point B. Point A is at (negative 8, negative 13) and point B is at (4, 11
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Please help thank you.
Brilliant_brown [7]
Question 1:
For that point where all the lines intersect to be an incenter, the following must be true
4x - 1 = 6x - 5
Subtract both sides by 6x
-2x -1 = -5
Add both sides by 1
-2x = -4
Divide both sides by -2
x= 2

Question 2:
Plug in x=2 into any of the two equations.

You get 7.

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4 years ago
PLEASE HELP WILL MARK BRAINLIEST Write the equation of the line parallel to the given line and passing through the given point.
Naily [24]

The parallel lines have the same slope.

The slope-intercept form: y = mx + b

m - a slope.

We have 6x + y = 4     |subtract 6x from both sides

y = -6x + 4 → m = -6.

The slope-point form:

y-y_1=m(x-x_1)

We have m = -6 and (-2, 3).

Substitute:

y-3=-6(x-(-2))\\\\y-3=-6(x+2)\\\\y-3=(-6)(x)+(-6)(2)\\\\y-3=-6x-12\qquad|+3\\\\y=-6x-9\qquad|+6x\\\\6x+y=-9

<h3>Answer: 6x + y = -9.</h3>
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3 years ago
Which inequality models this situation?
lora16 [44]
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lol
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