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zavuch27 [327]
3 years ago
8

I need help on both of those 4 problems

Mathematics
1 answer:
Masja [62]3 years ago
7 0
Are u trying to see if these r true and false?
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A clown had 10 balloons that he sold at a carnival dor 6 cents each. if he sold all 10 balloons, how mush money did he make​
saveliy_v [14]

Answer:

Step-by-step explanation:

You would do 10*0.06 to get 0.6

So her sold 60 cents worth of balloons

6 0
3 years ago
Read 2 more answers
What is 12.25 as a fraction
Finger [1]

Answer:

\large\boxed{12.25=\dfrac{49}{4}}

Step-by-step explanation:

12.\underbrace{25}_{2}=\dfrac{1225}{1\underbrace{00}_2}=\dfrac{1225:25}{100:25}=\dfrac{49}{4}\\\\12.25=12+0.25=12+\dfrac{25}{100}=12+\dfrac{25:25}{100:25}=12+\dfrac{1}{4}\\\\=\dfrac{12\cdot4}{4}+\dfrac{1}{4}=\dfrac{48+1}{4}=\dfrac{49}{4}

8 0
3 years ago
Mr. Collins ordered 8,000 oz of stone how many tons of stone did he order? ​
padilas [110]

Answer:

0.25.

Step-by-step explanation:

.

7 0
3 years ago
find the formula for a rational function that satisfies all of the following. its x-intercept is (-3,0). it has a vertical asymp
Norma-Jean [14]

Let that be

\\ \rm\Rightarrow y=\dfrac{a(f(x))}{g(x)}

Two vertical asymptotes at -1 and 0

\\ \rm\Rightarrow y=\dfrac{a(f(x)}{x(x+1)}

If we simply

\\ \rm\Rightarrow y=\dfrac{a(f(x)}{x^2+1}

  • Denominator has degree 2
  • Numerator should have degree as 2 and coefficient as 3 inorder to get horizontal asymptote y=3 means the quadratic equation should contain 3x²
  • But there should be a x intercept at -3 so one zeros should be -3

Find a equation

  • 3x²+9x

Find zeros

  • 3x²+9x=0
  • 3x(x+3)=0
  • x=0,-3

Horizontal asymptote

  • 3x²/x²
  • 3

So our equation is

\\ \rm\Rightarrow y=\dfrac{3x^2+9x}{x(x+1)}

Graph attached

4 0
2 years ago
Please help it would be much appreciated!
sergiy2304 [10]

Answer:

Part a) Option d

Part b) Option a

Step-by-step explanation:

Part a

if we look at the options given and the data available

Option a) x^4+9

Putting x= 2 we get (2^4) + 9 =25

Putting x= 3 we get (3^4) + 9 =90 but f(x) =125 so not correct option

Option b) (4^x)+9

Putting x= 2 we get (4^2) + 9 =25

Putting x= 3 we get (4^3) + 9 =73 but f(x) =125 so not correct option

Option c) x^5

Putting x= 2 we get (2^5)  =32 but f(x) =25 so not correct option

Option d) 5^x

Putting x= 2 we get (5^2)  =25

Putting x= 3 we get (5^3)  =125

Putting x= 4 we get (5^4)  =625

So Option d is correct.

Part (b)

3(2)^3x

can be solved as:

=3(2^3)^x

=3(8)^x

So, correct option is a

8 0
3 years ago
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