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Firdavs [7]
2 years ago
5

In a recent survey of 1002 people, 701 said that they voted in a recent presidential election. Voting records show that 61% of e

ligible voters actually did vote. a) Find the 95% confidence interval estimate of the proportion of people who say that they voted.
Mathematics
1 answer:
steposvetlana [31]2 years ago
7 0

Answer:

The 95% confidence interval estimate of the proportion of people who say that they voted

(0.67122 , 0.72798)

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

In a recent survey of 1002 people, 701 said that they voted in a recent presidential election.

Sample proportion

                          p = \frac{x}{n} = \frac{701}{1002} = 0.6996  

<u><em>Step(ii)</em></u>

The 95% confidence interval estimate of the proportion of people who say that they voted

(p^{-} - Z_{0.05} \sqrt{\frac{p(1-p)}{n} } , p^{-} + Z_{0.05} \sqrt{\frac{p(1-p)}{n} } )

(0.6996 - 1.96\sqrt{\frac{0.6996(1-0.6996)}{1002} } , 0.6996 + 1.96 \sqrt{\frac{0.6996(1-0.6996)}{1002} } )

(0.6996 - 1.96 X 0.01448 , 0.6996 + 1.96 X 0.01448)

(0.6996 - 0.02838 , 0.6996 + 0.02838)

(0.67122 , 0.72798)

<u><em>Final answer</em></u>:-

The 95% confidence interval estimate of the proportion of people who say that they voted

(0.67122 , 0.72798)

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Using a system of equations, it is found that Debbie worked 45 hours during the week.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are:

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Juan and Debbie each earn 9 per hour at their "jobs", and earned a total of 765 for the week, hence:

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Simplifying the expression by 9:

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More can be learned about a system of equations at brainly.com/question/24342899

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What we know:
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