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bixtya [17]
3 years ago
11

3(12x2+x+1)+12(12x2+x+1)=15(12x2+x+1)

Mathematics
2 answers:
Morgarella [4.7K]3 years ago
8 0

Answer:

infinite solutions

Step-by-step explanation:

3(12x2+x+1)+12(12x2+x+1)=15(12x2+x+1)

Combine like terms

3(12x2+x+1)+12(12x2+x+1)=15(12x2+x+1)

15(12x2+x+1) = 15(12x2+x+1)

Divide by 15

(12x2+x+1) = (12x2+x+1)

Since they are the same

x can be any real value

Vsevolod [243]3 years ago
6 0

Answer:

All real values of x

Step-by-step explanation:

3(12x²+x+1)+12(12x²+x+1)=15(12x²+x+1)

(12x² + x + 1)(3+12) = 15(12x²+x+1)

15(12x²+x+1) = 15(12x²+x+1)

Since both sides are identical, all real values of x will satisfy the equation

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yulyashka [42]

Answer:

12

Step-by-step explanation:

each letter can be used with each other 3 times and there are 4 letters so 12

5 0
3 years ago
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If a+b = 7, and a² +b²=25<br>then ab = ?​
Rama09 [41]

a2+b2=25

or, (a+b)^2-2ab=25

or, (7)^2-2ab=25 [a+b=7]

or, 49-25=2ab

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•°• ab=12....

3 0
3 years ago
What is the range of the equation
a_sh-v [17]

The range of the equation is y>2

Explanation:

The given equation is y=2(4)^{x+3}+2

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

y=2 \cdot 4^{x+3}+2

This can be written as y=2^{1+2(x+3)}+2

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

x=2^{1+2(y+3)}+2

Solving for y, we get;

x-2=2^{1+2(y+3)}

Applying the log rule, if f(x) = g(x) then \ln (f(x))=\ln (g(x)), then, we get;

\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)

Simplifying, we get;

(1+2(y+3)) \ln (2)=\ln (x-2)

Dividing both sides by \ln (2), we have;

2 y+7=\frac{\ln (x-2)}{\ln (2)}

Subtracting 7 from both sides of the equation, we have;

2 y=\frac{\ln (x-2)}{\ln (2)}-7

Dividing both sides by 2, we get;

y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}

Let us find the positive values for logs.

Thus, we have,;

x-2>0

     x>2

The function domain is x>2

By combining the intervals, the range becomes y>2

Hence, the range of the equation is y>2

7 0
4 years ago
Challenge question<br>please help<br>​
Pani-rosa [81]

Answer:

The 3 possible values of x are;

6, 4 and 2

Step-by-step explanation:

If the triangle is isosceles, then two of the sides must be equal

So we equate the sides, 2 at a time to get the different values of x

3x + 4 = 2x + 10

3x-2x = 10-4

x = 6

3x + 4 = x + 12

3x-x = 12-4

2x = 8

x = 8/2 = 4

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x = 2

7 0
3 years ago
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