Answer:
what?
Step-by-step explanation:
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From my understanding, there are 124 5 dollar bills which would equal $620.
The total money of the value is $840 then you would subtract. $840-$620=$220.
Divide that by ten so, $220/10= 22.
She has 22 ten dollar bills.
Ok
A=bh
plug in
126 square meters=6b
126/6 6/6
21=b
base length=21meters
In probability, problems involving arrangements are called combinations or permutations. The difference between both is the order or repetition. If you want to arrange the letters regardless of the order and that there must be no repetition, that is combination. Otherwise, it is permutation. Therefore, the problem of arrange A, B, C, D, and E is a combination problem.
In combination, the number of ways of arranging 'r' items out of 'n' items is determined using n!/r!(n-r)!. In this case, you want to arrange all 5 letters. So, r=n=5. Therefore, 5!/5!(505)! = 5!/0!=5!/1. It is simply equal to 5! or 120 ways.
