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3 years ago

X^2+4=square root 13

Mathematics

1 answer:

beks73 [17]3 years ago

5 0

Answer:

$\large\boxed{x=-\sqrt{\sqrt{13}-4}}\ \vee\ x=\sqrt{\sqrt{13}-4}}$

Step-by-step explanation:

$x^2+4=\sqrt{13}\qquad\text{subtract 4 from both sides}\\\\x^2+4-4=\sqrt{13}-4\\\\x^2=\sqrt{13}-4\Rightarrow x=-\sqrt{\sqrt{13}-4}}\ \vee\ x=\sqrt{\sqrt{13}-4}$

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Given f(x)=8x+13 and g(x)=x^2-5x, find (f-g)x

uysha [10]

(f-g)x= -x²+13x+13

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3 years ago

Find mZ3 if mZ5 = 145º and mZ4 = 45°

trapecia [35]

9514 1404 393

Answer:

C. 100°

Step-by-step explanation:

The exterior angle is equal to the sum of the remote interior angles.

∠5 = ∠3 +∠4

145° = ∠3 +45° . . . . fill in the given values

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3 years ago

What percent of 132 grams is 43.2 grams ??

alexira [117]

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3 years ago

f(x) = 3 cos(x) 0 ≤ x ≤ 3π/4 evaluate the Riemann sum with n = 6, taking the sample points to be left endpoints. (Round your ans

Kruka [31]

Answer:

$\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx\approx 3.099558$

Step-by-step explanation:

We want to find the Riemann sum for $\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx$ with n = 6, using left endpoints.

The Left Riemann Sum uses the left endpoints of a sub-interval:

$\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_0)+f(x_1)+2f(x_2)+...+f(x_{n-2})+f(x_{n-1})\right)$

where $\Delta{x}=\frac{b-a}{n}$ .

Step 1: Find $\Delta{x}$

We have that $a=0, b=\frac{3\pi }{4}, n=6$

Therefore, $\Delta{x}=\frac{\frac{3 \pi}{4}-0}{6}=\frac{\pi}{8}$

Step 2: Divide the interval $\left[0,\frac{3 \pi}{4}\right]$ into n = 6 sub-intervals of length $\Delta{x}=\frac{\pi}{8}$

$a=\left[0, \frac{\pi}{8}\right], \left[\frac{\pi}{8}, \frac{\pi}{4}\right], \left[\frac{\pi}{4}, \frac{3 \pi}{8}\right], \left[\frac{3 \pi}{8}, \frac{\pi}{2}\right], \left[\frac{\pi}{2}, \frac{5 \pi}{8}\right], \left[\frac{5 \pi}{8}, \frac{3 \pi}{4}\right]=b$

Step 3: Evaluate the function at the left endpoints

$f\left(x_{0}\right)=f(a)=f\left(0\right)=3=3$

$f\left(x_{1}\right)=f\left(\frac{\pi}{8}\right)=3 \sqrt{\frac{\sqrt{2}}{4} + \frac{1}{2}}=2.77163859753386$

$f\left(x_{2}\right)=f\left(\frac{\pi}{4}\right)=\frac{3 \sqrt{2}}{2}=2.12132034355964$

$f\left(x_{3}\right)=f\left(\frac{3 \pi}{8}\right)=3 \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}}=1.14805029709527$

$f\left(x_{4}\right)=f\left(\frac{\pi}{2}\right)=0=0$

$f\left(x_{5}\right)=f\left(\frac{5 \pi}{8}\right)=- 3 \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}}=-1.14805029709527$

Step 4: Apply the Left Riemann Sum formula

$\frac{\pi}{8}(3+2.77163859753386+2.12132034355964+1.14805029709527+0-1.14805029709527)=3.09955772805315$

$\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx\approx 3.099558$

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3 years ago

Find equation to the given value of the curve x=t^5+1, y=t^6+t, and t=-1. please help I keep getting y=-1.4x and it is incorrect

irakobra [83]

Well for the function of x we have x=t^5+1 and we know t= -1

So you plug in -1 instead of the t and you will get x=(-1)^5+1
Now just resolve that equation to get the value of x

x = (-1)^5+1 = -1+1 = 0 So x=0

Do the same with y and you’ll get y=2

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3 years ago