Answer:
1
Step-by-step explanation:
What is the largest of 3 consecutive integers such that the sum of the first and third is equal to three times the second?
3 consecutive angles
= x, x + 1, x + 2
We are told in the question that:
the sum of the first and third is equal to three times the second
a + c = 3b
x + x + 2 = 3(x + 1)
2x + 2 = 3x + 3
3x - 2x = 2 - 3
x = -1
The largest of the three numbers is the third number
= x + 2
x + 2 = -1 + 2
The third and largest number is 1
Answer: 21 goodluck
3
The assumed frequency of defects is 2/16.
When we apply this rate to 24, (2/16)*24, we get 3.
Therefore, we can assume around 3 defective boxes tomorrow.
