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2 years ago

What is the largest of 3 consecutive integers such that the sum of the first and third is equal to three times the second.

Mathematics

1 answer:

Norma-Jean [14]2 years ago

4 0

Answer:

Step-by-step explanation:

What is the largest of 3 consecutive integers such that the sum of the first and third is equal to three times the second?

3 consecutive angles

= x, x + 1, x + 2

We are told in the question that:

the sum of the first and third is equal to three times the second

a + c = 3b

x + x + 2 = 3(x + 1)

2x + 2 = 3x + 3

3x - 2x = 2 - 3

x = -1

The largest of the three numbers is the third number

= x + 2

x = -1

x + 2 = -1 + 2

The third and largest number is 1

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Write the equation of a line perpendicular to 2x + 3y = 4 and passing through (-3,-5).

Tasya [4]

Answer:

Step-by-step explanation:

A line perpendicular to the given line has a slope that is the negative inverse of the reference line.

Rewrite the given equation in the format of y=mx+b, where mi is the slope and b is the y-intercept (the value of y when x = 0.

2x + 3y = 4

3y=-2x+4

y = -(2/3)X + (4/3)

The reference slope is -(2/3). The negative inverse is (3/2), which will be the slope of a perpendicular line. We can write the new line as:

y = (3/2)x + b

Any value of b will still result in a line that is perpendicular. But we want a value of b that will shift the line so that it intersects the point (-3,-5). Simply enter this point in the above equation and solve for b.

y = (3/2)x + b

-5 = (3/2)(-3) + b

-5 = -(9/2) + b

-5 = -4.5 + b

b = - 0.5

The equation of the line that is perpendicular to 2x + 3y = 4 and includes point (-3,-5) is

y = (3/2)x - 0.5

6 0

1 year ago

My estimate was 2,808 is that a reasonable estimate and why

vova2212 [387]

My estimate was 2,808 is that a reasonable estimate and why

312*9

9*2=18>>9*10=90>>9*300=2700

2700+18+90=>>2,808

5 0

3 years ago

Write each expression in quadratic form, if possible.. 5X^4 + 2X^2 - 8

Igoryamba

5X^4 + 2X^2 – 8

Its quadratic form is 5(x²)² +2x² -8

Let be X²=p, so the final expression is 5p²+2p-8

4 0

2 years ago

Brooks built two similar wooden chests in the shape of rectangular prisms. She used 16 pints of paint to cover the outside of th

tester [92]

Choices: A. 16/9 B. 4/3 C. 32/9 D. 64/27

Given:
number of pints used for larger chest = 16 pints
number of pints used for smaller chest = 9 pints

Ratio of the volume of the larger chest compared to the smaller chest.

We will use the number of pints used in lieu of the volume of each chest.

16 / 9 is the ratio. Choice A.

3 0

3 years ago

Find the points on the cone z2 = x2 + y2 that are closest to the point (6, 2, 0).

aliya0001 [1]

Answer:

The closest points on the cone are;

(6, 2, -√10) and (6, 2, √10)

Step-by-step explanation:

Let B(x, y, z) denote a point on the cone.

Therefore, the distance between the points (6, 2, 0) and B(x, y, z) is;

d = √[(x - 6)² + (y - 2)² + (z - 0)²]

d = √[(x - 6)² + (y - 2)² + z²]

Since we are given that z² = x² + y², we now have;

d = √[(x - 6)² + (y - 2)² + x² + y²]

Taking the square of both sides gives;

d² = [(x - 6)² + (y - 2)² + x² + y²]

x² is an increasing function. Thus, minimizing d is also the same as to minimize f (x, y) = d²

Thus, f' = 0. So;

df/dx = 2(x - 6) + 2x = 0

2x - 12 + 2x = 0

4x = 12

x = 12/4

x = 3

Similarly,

df/dy = 2(y - 2) + 2y = 0

2y - 4 + 2y = 0

4y - 4 = 0

4y = 4

y = 4/4

y = 1

Now,from earlier;

z² = x² + y²

Thus;

z = ±√(3² + 1²)

z = ±√10

Thus, the closest points on the cone are;

(6, 2, -√10) and (6, 2, √10)

7 0

3 years ago