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laila [671]
3 years ago
10

What is the largest of 3 consecutive integers such that the sum of the first and third is equal to three times the second.

Mathematics
1 answer:
Norma-Jean [14]3 years ago
4 0

Answer:

1

Step-by-step explanation:

What is the largest of 3 consecutive integers such that the sum of the first and third is equal to three times the second?

3 consecutive angles

= x, x + 1, x + 2

We are told in the question that:

the sum of the first and third is equal to three times the second

a + c = 3b

x + x + 2 = 3(x + 1)

2x + 2 = 3x + 3

3x - 2x = 2 - 3

x = -1

The largest of the three numbers is the third number

= x + 2

x = -1

x + 2 = -1 + 2

The third and largest number is 1

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Answer:

3 3/7 or 24/7 mins

Step-by-step explanation:

Let total job = X

Jeff's rate = X/6

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Combined rate = X/6 + X/8

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7X/24 = X/T

T = X ÷ (7X/24)

T = X × (24/7X)

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Shortcut:

T = product of individual times/sum of individual times

T = (6×8)/(6+8)

T = 48/14

T = 24/7

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3 years ago
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Answer:

H) B= 13

Step-by-step explanation:

<em>5 + b = 18</em>

<em>F) 5 + 5 = 10 so not equal to 18. It is not a solution</em>

<em>H) 5 + 13 = 18 it's equal . so it is the solution</em>

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Answer:

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Step-by-step explanation:

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we can divide the figure into three other rectangles

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