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riadik2000 [5.3K]

3 years ago

7

Company A charges a base rate of $5 per month, plus 4 cents per minute that you are on the phone. Company B charges a base rate

of only $2 per month, but they charge 10 cents per minute used.

1 answer:

Afina-wow [57]3 years ago

4 0

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Kalani bought 2.5 pounds oranges for $1.58 per pound.how much did kalani spend on oranges ?

Tcecarenko [31]

To find the answer for this simply multiply 2.5 by 1.58

2.5 x 1.58= 3.95

So Kalani spent a total of $3.95 on oranges!

6 0

3 years ago

Read 2 more answers

You are thinking about opening a restaurant and are searching for a good location. From the research you have done, you know tha

adell [148]

A type I and type II error of the given question are respectively;

A) concluding that the local mean income exceeds $45000 when in fact it does not and therefore opening a restaurant in a locale that would not support it.

B) concluding that the local mean income does not exceed $45000 when in fact it does not and therefore deciding not to open a restaurant in a locale that would support it.

<h3>What is Type 1 and a Type II error?</h3>

In statistics, a type I error simply means rejecting the null hypothesis when it's actually true. Meanwhile, a Type II error means failing to reject the null hypothesis when it's actually false.

Now, in this question what we will consider to be a type I error is concluding that the local mean income exceeds $45000 when in fact it does not and therefore opening a restaurant in a locale that would not support it.

A type II error will be concluding that the local mean income does not exceed $45000 when in fact it does not and therefore deciding not to open a restaurant in a locale that would support it.

Read more about Type I and II errors at; brainly.com/question/16012410

3 0

2 years ago

What is the value of a and b?

prohojiy [21]

A = 34 x 2 = 68
b = 56/2 = 28

hope it helps

3 0

2 years ago

Read 2 more answers

4x2 is the GCF of this polynomial.

viva [34]

Answer:

Correct option is B

Step-by-step explanation:

Note that

$20x^2y=2\cdot 2\cdot 5\cdot x\cdot x\cdot y,$

$56x^3=2\cdot 2\cdot 2\cdot 7\cdot x\cdot x\cdot x.$

If the mystery term is $22x^3=2\cdot 11\cdot x\cdot x\cdot x,$ then the

$GCF(20x^2y,56x^3,22x^3)=2\cdot x\cdot x=2x^2.$

If the mysteyr term is $24x^2y=2\cdot 2\cdot 2\cdot 3\cdot x\cdot x\cdot y,$ then

$GCF(20x^2y,56x^3,24x^2y)=2\cdot 2\cdot x\cdot x=4x^2.$

If the mysteyr term is $26x^2y=2\cdot 13\cdot x\cdot x\cdot y,$ then

$GCF(20x^2y,56x^3,26x^2y)=2\cdot x\cdot x=2x^2.$

If the mysteyr term is $28y^3=2\cdot 2\cdot 7\cdot y\cdot y\cdot y,$ then

$GCF(20x^2y,56x^3,28y^3)=2\cdot 2=4.$

Thus, correct option is B

8 0

3 years ago

Read 2 more answers

If mc021-1.jpg and mc021-2.jpg, what is the range of mc021-3.jpg?

sergeinik [125]

$u(x)=-2x^2+3$ , and $v(x)= \frac{1}{x}$ ,

we want to find the range of $(u\circ v)(x)=u(v(x))$

Notice that Whatever value v can possibly produce, that is the Range of v, becomes the range of u.

Then whatever u produces for these values, is the range of u(v(x))

So, first find range of v: clearly the domain of v is R-{0}, as v(0) makes no sense.

We check what values c can v produce:

$\frac{1}{x}=c\\\\x= \frac{1}{c}$ ,

this means that any c (for now) can be produced... it is enough to let x=1/c

this also means that c cannot be equal to 0 as 1/c makes no sense if c=0.

Thus the range of v is R-{0},

Now we check the range of u(v(x)) for v(x)∈R-{0},

assume we want to produce a value c, so:

$c=-2x^2+3\\\\-2x^2=c-3\\\\x^2= \frac{c-3}{-2}$

since the left side is always positive or 0, for x=0, the right hand side expression must also be positive or zero, which means c-3 must be negative or 0,

thus c-3≤0; c≤3. Here recall that x in u(x) cannot be 0, so c<3.

Answer: The range of u(v(x)) is (-infinity, 3)

8 0

3 years ago