<h3>given:</h3>
<h3>to find:</h3>
the radius of the given ball (sphere).
<h3>solution:</h3>
<u>therefore</u><u>,</u><u> </u><u>the</u><u> </u><u>radius</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>ball</u><u> </u><u>is</u><u> </u><u>6</u><u> </u><u>cm</u><u>.</u>
note: refer to the picture I added on how you can change r as the subject of the formula.
Answer:
Step-by-step explanation:
The sine of an angle is defined as the ratio between the opposite side and the hypotenuse of a given right-angled triangle;
sin x = ( opposite / hypotenuse)
The opposite side to the angle x is thus 1 unit while the hypotenuse is 3 units. We need to determine the adjacent side to the angle x. We use the Pythagoras theorem since we are dealing with right-angled triangle;
The adjacent side would be;
The cosine of an angle is given as;
cos x = (adjacent side / hypotenuse)
Therefore, the cos x would be;
The percentage of eighth-graders that chose History as their favorite subject is 19%
<h3>Percentages and proportion</h3>
From the given table, we have the following parameters
Total students in the 8th grade = 124 students
Total number of 8th graders that chose history = 11 + 12
Total number of 8th graders that chose history = 23
Required percentage = 23/124 * 100
Required percentage = 19%
Hence the percentage of eighth-graders that chose History as their favorite subject is 19%
Learn more on percentages here: brainly.com/question/24304697
Answer:
A
Step-by-step explanation:
Because I know how to do it
Answer:
The pairs of integer having two real solution for are
Step-by-step explanation:
Given
Now we will solve the equation by putting all the 6 pairs so we get the following
for
for
for
for
for
for
The above all are Quadratic equations inn general form
where we have a,b and c constant values
So for a real Solution we must have
for we have
which is less than 0 ∴ not a real solution.
for we have
which is greater than 0 ∴ a real solution.
for we have
which is greater than 0 ∴ a real solution.
for we have
which is greater than 0 ∴ a real solution.
for we have
which is equal to 0 ∴ a real solution.
for we have
which is less than 0 ∴ not a real solution.