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iogann1982 [59]
3 years ago
14

For brainiest:):):):):):)

Mathematics
1 answer:
salantis [7]3 years ago
8 0

Answer:

C

Step-by-step explanation:

The graph is showing distance traveled, not acceleration.

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wrote this expression on the board: 2 12 ÷ 34 She asked her students to write a word problem that could be solved using the expr
balandron [24]

Step-by-step explanation:

The equation equation looks incomplete. However assuming it to be 212÷34.

This becomes a simple case of division. Now forming a world problem on this equation.

Consider there are 212 chocolates to be distributed among 34 children, such that each child gets equal number of chocolates. Find how many chocolate does each child got.

Simply divide 212 by 34 to get the answer =212/34

7 0
2 years ago
An arc has a central angle of 1.8 radians and a radius of 20
Nutka1998 [239]

Answer:

a) <em>Arc  length (l) = 36 inches</em>

b)

The nearest angle in degrees θ = 103.18°

Step-by-step explanation:

<u><em>Step(i):</em></u>-

An arc has a central angle of 1.8 radians and a radius of 20  inches.

Given arc has a central angle of 1.8 radians and

radius of circle = 20 inches

Given arc has a central angle (θ ) = 1.8 radians

<em> Arc  length (l) = r θ </em>

<em>                  l = 20 × 1.8 radians</em>

<em>               l  = 36</em>

The length of arc = 36 inches

b)

<em>we will convert radians to degree</em>

<em> 1.8 × 180° / π =  324° / π ≅ 103.18°</em>

The nearest angle in degrees θ = 103.18°

                           

3 0
3 years ago
Use matrices to solve the system of equations if possible. Use Gaussian elimination with back substitution or gauss Jordan elimi
CaHeK987 [17]

In matrix form, the system is given by

\begin{bmatrix} -1 & 1 & -1 \\ 2 & -1 & 1 \\ 3 & 2 & 1 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} -20 \\ 29 \\ 29 \end{bmatrix}

I'll use G-J elimination. Consider the augmented matrix

\left[ \begin{array}{ccc|c} -1 & 1 & -1 & -20 \\ 2 & -1 & 1 & 29 \\ 3 & 2 & 1 & 29 \end{array} \right]

• Multiply through row 1 by -1.

\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 2 & -1 & 1 & 29 \\ 3 & 2 & 1 & 29 \end{array} \right]

• Eliminate the entries in the first column of the second and third rows. Combine -2 (row 1) with row 2, and -3 (row 1) with row 3.

\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 5 & -2 & -31 \end{array} \right]

• Eliminate the entry in the second column of the third row. Combine -5 (row 2) with row 3.

\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 0 & 3 & 24 \end{array} \right]

• Multiply row 3 by 1/3.

\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 0 & 1 & 8 \end{array} \right]

• Eliminate the entry in the third column of the second row. Combine row 2 with row 3.

\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & 0 & -3 \\ 0 & 0 & 1 & 8 \end{array} \right]

• Eliminate the entries in the second and third columns of the first row. Combine row 1 with row 2 and -1 (row 3).

\left[ \begin{array}{ccc|c} 1 & 0 & 0 & 9 \\ 0 & 1 & 0 & -3 \\ 0 & 0 & 1 & 8 \end{array} \right]

Then the solution to the system is

\boxed{x=9, y=-3, z=8}

If you want to use G elimination and substitution, you'd stop at the step with the augmented matrix

\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 0 & 1 & 8 \end{array} \right]

The third row tells us that z=8. Then in the second row,

y-z = -11 \implies y=-11 + 8 = -3

and in the first row,

x-y+z=20 \implies x=20 + (-3) - 8 = 9

5 0
2 years ago
Harry has 8 more marbles than hermione. together they have 40 marbles. how many does each have?​
aksik [14]

Answer:

Harry has 24; Hermione has 16

3 0
3 years ago
Read 2 more answers
PLEASE HELP!! will give brainliest. answer choices and question are in the photo.
Ivan

Answer:

-17,-6and 1,-6

Step-by-step explanation:

4 0
3 years ago
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