How to find the perimeter

2 answers:

6 0

If you're trying to find the perimeter of a specific problem, you can add a file. To solve perimeter for any problem, you add all the side lengths. Hope that helps! :)

Alchen [17]3 years ago

3 0

To find perimeter all you have to do is add the sides together. i hope that this helps, and i hope that you have a nice rest of your day :)

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zmey [24]

1) 5.1
2)7.9
3) 4
4)20
5)8.9
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7)5.2
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8 0

2 years ago

The heat in the house is set to keep the minimum and maximum temperatures (in degrees Fahrenheit) according to the equation |x –

olga2289 [7]

Given the equation $|x-72.5|=4$ .

When x is maximum, we have

$|x-72.5|= x-72.5$ . Hence $x-72.5 =4\\x=76.5$

The maximum temperature is $76.5\; ^oF$

When x is minimum, we have

$|x-72.5|=72.5-x$ . Hence $72.5-x =4\\x=68.5$

The minimum temperature is $68.5\; ^oF$

7 0

3 years ago

Read 2 more answers

What two numbers multiply to 630 and add to -57

sveta [45]

-15 and -42 both add to -57 and multiply to 630

5 0

3 years ago

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The vertices of a triangle ABC are A(7, 5), B(4, 2), and C(9, 2). What is measure of angle ABC? 30° 45° 56.31° 78.69°

GenaCL600 [577]

The measure of angle ABC is 45°

Explanation

Vertices of the triangle are: A(7, 5), B(4, 2), and C(9, 2)

According to the diagram below....

Length of the side BC (a) $=\sqrt{(4-9)^2+(2-2)^2}= \sqrt{25}= 5$

Length of the side AC (b) $= \sqrt{(7-9)^2 +(5-2)^2}= \sqrt{4+9}=\sqrt{13}$

Length of the side AB (c) $= \sqrt{(7-4)^2 +(5-2)^2} =\sqrt{9+9}=\sqrt{18}$

We need to find ∠ABC or ∠B . So using Cosine rule, we will get...

$cosB= \frac{a^2+c^2-b^2}{2ac} \\ \\ cos B= \frac{(5)^2+(\sqrt{18})^2-(\sqrt{13})^2}{2*5*\sqrt{18} }\\ \\ cosB= \frac{25+18-13}{10\sqrt{18}} =\frac{30}{10\sqrt{18}}=\frac{3}{\sqrt{18}}\\ \\ cosB=\frac{3}{3\sqrt{2}} =\frac{1}{\sqrt{2}}\\ \\ B= cos^-^1(\frac{1}{\sqrt{2}})= 45 degree$