3 years ago

Eli makes a dozen cupcakes

1 answer:

7 0

Answer:

5/12 I think?? Hope this helps!

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Rasek [7]

Pretty sure it's the last one.

5 0

3 years ago

Kryger [21]

We're looking for $a,b$ such that

$\dfrac{9x-20}{(x+6)^2}=\dfrac a{x+6}+\dfrac b{(x+6)^2}$

Multiplying both sides by $(x+6)^2$ gives us

$9x-20=a(x+6)+b$

Notice that when $x=-6$ , the term involving $a$ vanishes and we're left with

$9(-6)-20=b\implies b=-74$

Then

$9x-20=a(x+6)-74=ax+6a-74\implies a=9$

so that

$\dfrac{9x-20}{(x+6)^2}=\boxed{\dfrac9{x+6}-\dfrac{74}{(x+6)^2}}$

3 0

3 years ago

Anarel [89]

Answer:

by factorising it we get , (2x + 1) • (x + 3)

Step-by-step explanation:

for solution see the attached picture. ...

5 0

3 years ago

shusha [124]

Answer:

Step-by-step explanation:

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3 years ago

Strike441 [17]

It would take him 66 minutes longer to deliver 100 papers than 72 papers

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3 years ago