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tankabanditka [31]
3 years ago
8

Line 'L' is horizontal and passes through (-5,8). Line 'L is vertical and passes through $(4,-1)$. Find the point of intersectio

n of $\ell_1$ and $\ell_2$.
Mathematics
2 answers:
Firlakuza [10]3 years ago
8 0

Answer:

The two lines intersect at (4,8).

Elanso [62]3 years ago
4 0
<h3>The two lines intersect at (4,8)</h3>

Every y coordinate on the horizontal line is the same, so each point has a y coordinate of y = 8. This is to be able to pass through (-5,8)

Every x coordinate on the vertical line is the same, so each point has an x coordinate of x = 4. This is to be able to pass through (4,-1)

Put this together to get the answer (x,y) = (4,8)

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Answer:

Step-by-step explanation:

eq. of any line through (1,2) with slope m is

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if the line is parallel to x-axis then y=2

if the line is parallel to y-axis then x=1

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3 years ago
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Using the Triangle Sum Theorem, find x and the missing angles (2x +1) (5x +5) x= Angle (2x+1) = Angle (5x+5) =​
Arte-miy333 [17]

Answer:

x = 12

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In the given right triangle,

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7x = 180 - 96

x = \frac{84}{7}

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Angle (5x + 5)° = 5(12) + 5 = 65°

Therefore, all three angles of the right triangle are 25°, 90° and 65°.

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3 years ago
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