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tankabanditka [31]
3 years ago
8

Line 'L' is horizontal and passes through (-5,8). Line 'L is vertical and passes through $(4,-1)$. Find the point of intersectio

n of $\ell_1$ and $\ell_2$.
Mathematics
2 answers:
Firlakuza [10]3 years ago
8 0

Answer:

The two lines intersect at (4,8).

Elanso [62]3 years ago
4 0
<h3>The two lines intersect at (4,8)</h3>

Every y coordinate on the horizontal line is the same, so each point has a y coordinate of y = 8. This is to be able to pass through (-5,8)

Every x coordinate on the vertical line is the same, so each point has an x coordinate of x = 4. This is to be able to pass through (4,-1)

Put this together to get the answer (x,y) = (4,8)

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What expression represents six times a number plus 8 times a number
zheka24 [161]
6n + 8n

Which is 6 * n + 6 * 8, n being a number. 

4 0
3 years ago
Sue receives a monthly salary of $500. She also receives a sales commision of
artcher [175]

Answer:

2000 because you got to subtract

5 0
2 years ago
Keegan leans an 18-foot ladder against the top of a wall. The bottom of the ladder is 4.5 feet from the base of the wall. What i
zaharov [31]

Answer: C. 17.5 feet

Step-by-step explanation:

The attached photo shows the triangle ABC formed by the ladder and the wall. It is a right angle triangle because one of its angles is 90 degrees. The ladder is the hypotenuse of the triangle. To determine the height of the wall, we would find BC by applying Pythagoras theorem

Hypotenuse^2 = opposite ^2 + adjacent^2

18^2 + 4.5^2 + BC^2

BC^2 = 324 - 20.25 = 303.75

BC = √303.75 = 17.5 feet.

3 0
3 years ago
Aidan makes 12 bracelets on Monday.He makes 8 more bracelets each day from Tuesday through Thursday.How many bracelets does Aida
r-ruslan [8.4K]
Well if he started with 12 and made 8 each day from that point foward that would mean 8 times 4 plus 12 so the answer would be 44 bracelets. but if he makes 12 on friday then it would be 48 bracelets.
4 0
2 years ago
Solve using the quadratic formula 3x^2+11x+5=0
storchak [24]

Answer:

3x^2 + 11x + 5 = 0 : x = \frac{-11 + \sqrt{61} }{6} , x = \frac{-11 - \sqrt{61} }{6}

Decimal:

(x = -0.53162..., x = -3.13504...)

Step-by-step explanation:

3x^2+11x+5=0

Solve with the quadratic formula:

For a quadratic equation of the form ax^2+bx+c=0 the solutions are:

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

For a=3,\:b=11,\:c=5:\quad x_{1,\:2}=\frac{-11\pm \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}

x=\frac{-11 + \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 + \sqrt{61} }{6}

x=\frac{-11 - \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 - \sqrt{61} }{6}

The solutions to the quadratic equation are:

x=\frac{-11+\sqrt{61}}{6},\:x=\frac{-11-\sqrt{61}}{6}

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day! =)

8 0
3 years ago
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