We have 5 ft 9 in = 69 in, so
P(X > 69) = P((X - 64.1)/2.5 > (69 - 64.1)/2.5) = P(Z > 1.96)
where X and Z both represent women's heights, but Z is normally distributed with mean 0 and s.d. 1.
Then consulting a table of z-scores, you'll find that P(Z > 1.96) ≈ 0.025. So approximately 2.5% of women are taker than 5'9''.
A.) Angle TRS
The other angles do not form straight angles.
Answer:
i think the answer is 43 degrees but i dont know
Answer:
-1/2
Step-by-step explanation:
Let's find the mean of all the values first.
6.3+6.4+6.5+6.6+6.8+6.8+7.5= 46.9
Let's divide by the number of values.
46.9÷7=
6.7
Now let's find the distance that each number is away from 6.7 and find the mean of those numbers.
0.4+0.3+0.2+0.1+0.1+0.1+0.8=
.2857
≈ 0.3
So, the absolute deviation is 0.3.
