as you already know, to get the inverse of any expression we start off by doing a quick switcheroo on the variables and then solving for "y", let's do so.
![\stackrel{h(x)}{y}~~ = ~~6\sqrt[3]{2x+5}-1\implies \stackrel{\textit{quick switcheroo}}{x~~ = ~~6\sqrt[3]{2y+5}-1} \\\\\\ x+1=6\sqrt[3]{2y+5}\implies \cfrac{x+1}{6}=\sqrt[3]{2y+5}\implies \left( \cfrac{x+1}{6} \right)^3=\left( \sqrt[3]{2y+5} \right)^3](https://tex.z-dn.net/?f=%5Cstackrel%7Bh%28x%29%7D%7By%7D~~%20%3D%20~~6%5Csqrt%5B3%5D%7B2x%2B5%7D-1%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bquick%20switcheroo%7D%7D%7Bx~~%20%3D%20~~6%5Csqrt%5B3%5D%7B2y%2B5%7D-1%7D%20%5C%5C%5C%5C%5C%5C%20x%2B1%3D6%5Csqrt%5B3%5D%7B2y%2B5%7D%5Cimplies%20%5Ccfrac%7Bx%2B1%7D%7B6%7D%3D%5Csqrt%5B3%5D%7B2y%2B5%7D%5Cimplies%20%5Cleft%28%20%5Ccfrac%7Bx%2B1%7D%7B6%7D%20%5Cright%29%5E3%3D%5Cleft%28%20%5Csqrt%5B3%5D%7B2y%2B5%7D%20%5Cright%29%5E3)

Answer:
B.
Step-by-step explanation:
Take the square root of x^2 which would make the left side x and the right side the square root 5
Cylinder Volume = <span><span>¼ • </span><span>π • d² • height</span></span>
<span>
12,464.27 = .25 * PI * 23^2 * height
height = </span><span>12,464.27 /</span><span> .25 * PI * 23^2 </span>
height = 12,464.27 /<span> .25 * PI * 529
</span>height = 12,464.27 / <span><span><span>415.4756284373
</span>
</span>
</span>
<span>
</span><span>height = 30 mm
The vertical cross-section would be 23 mm * 30 mm =
690 SQUARE millimeters (NOT cubed as the answer says).
answer is C
</span>
Answer:
In group A, they have at least one 90 degree angle. In Group B, they do not have any 90 degree angles.
It will take Lauren 1.25 seconds to hit the water.
With the given information, we can write the following quadratic equation.

Now, just use the quadratic formula to solve the equation.
You will get 1.25 and -0.75 as the zeros of the equation (where Laruen hits the water).
Only 1.25 makes sense in the context of this problem.