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Yuki888 [10]
3 years ago
5

5. We can perform the logical operations on strings of bits by considering each pair of corresponding bits separately (called bi

twise operation). Given two eight bit strings A = 10110001 and B = 10101100, evaluate the eight bit result after the following logical operations: (2 pts each)
Mathematics
1 answer:
finlep [7]3 years ago
6 0

Answer:

Bitwise OR operation = 111011101

             AND operation = 10100000

             NOT operation:  01001110 (NOT A)

              XOR operation: 00011101

Step-by-step explanation:

OR operation:  A + B = adding the two binary numbers together, starting from the least significant bit (LSB) and moving to the Most significant bit (MSB)

AND operation: A*B, multiplying the two binary numbers together.

NOT: taking the opposite of each binary digit

XOR: if either of the two binary numbers is 1, then the result is 1, but if they are both 1 or both 0, then the result becomes 0.

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Help me Please....................
MakcuM [25]

9514 1404 393

Answer:

  1.3363

Step-by-step explanation:

The basic idea here is to find an expression for the direction vector between a point on L1 and a point on L2. Then, solve for the points on L1 and L2 that make that vector perpendicular to both lines L1 and L2. (The dot product of direction vectors is zero.) The distance between the points found is the shortest distance between the lines.

__

Let P be a point on L1. Then the parametric equation for P is ...

  P = (6t, 0, -t) . . . . . . origin + t × direction vector

Let Q be a point on L2. The direction vector for L2 is given by the difference between the given points. It is (4-1, 1-(-1), 6-1) = (3, 2, 5). Then the parametric equation for Q is ...

  Q = (3s+1, 2s-1, 5s+1) . . . . (1, -1, 1) + s × direction vector

The direction vector for PQ is ...

  Q -P = (3s+1-6t, 2s-1, 5s+1+t)

The dot product of this and the two lines' direction vectors will be zero:

  (3s+1-6t, 2s-1, 5s+1+t)·(6, 0, -1) = 0 = 13s -37t +5 . . . perpendicular to L1

  (3s+1-6t, 2s-1, 5s+1+t)·(3, 2, 5) = 0 = 38s -13t +6 . . . perpendicular to L2

The solution to these equations is ...

  s = -157/1237

  t = 112/1237

Then (Q-P) becomes (94, -1551, 564)/1237, and its length is ...

  |PQ| = √(94² +1551² +564²)/1237 ≈ 1.3363

The distance between the two lines is about 1.3363 units.

8 0
3 years ago
What is the value of x
Lostsunrise [7]

Answer: your answer is 36.3 cause it's half of 72.6.

Step-by-step explanation:

7 0
2 years ago
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8_murik_8 [283]

Answer:

d.

Step-by-step explanation:

The red graph is the black one times 2.

So y = 2 f(x). which is the same as y/2 = f(x) (divide by 2).

7 0
3 years ago
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4. The quotient of x and 7 is 5 more than three times x.
Lostsunrise [7]

Well,

it says The quatient of x and seven is 5 more than three times x

The quotient = x/7

three times x = 3x

x/7 = 3x + 5 This is the answer

8 0
1 year ago
Expand and simplify 9w(3x-4y)-5w(x+y)
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3 years ago
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