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3 years ago

A 3 liter bottle of juice costs $5.70 What is the unit price for 1 liter of juice?

Mathematics

2 answers:

Rzqust [24]3 years ago

7 0

Answer:

$1.90

Step-by-step explanation:

First, write out what you know.

So, you know that you have 3 liters.

Together, they cost $5.70.

You want to know the unit price, for 1 liter.

Therefore, you would divide $5.70 by 3:

$\frac{5.70}{3}=\frac{1.90}{1}=1.90$

This means that the unit price, for 1 liter of juice, would be $1.90.

Galina-37 [17]3 years ago

3 0

Answer:

$1.90

Step-by-step explanation:

Divide 5.7 by 3 to get your answer.

$\frac{5.7}{3}$ = 1.9

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Answer:

p = (1÷8)×(1÷7)×(1÷6)

Step-by-step explanation

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(1÷8)×(1÷7)×(1÷6) = 0,002976190476

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3 years ago

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George is helping the manager of the local produce market expand her business by distributing flyers

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Answer:

20 + 0.05x ≥ 65

Step-by-step explanation:

20 is by itself since thats what he earns extra per day.

Since he earns 0.05 per flyer, that means we are going to need a variable since we don't know how many flyers he passes. Let x be equal to that.

Since he wants to make at LEAST 65 we are going to use the greater than or equal to symbol since he doesn't want to make less than that.

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3 years ago

If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the

Brrunno [24]

Answer:

$\left(100\pi - 150\sqrt{3}\right)$ square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be $10$ inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment $\sf CH$ be a height on side $\sf AB$ . Since this triangle is equilateral, the size of each internal angle will be $\sf 60^\circ$ . The length of segment

$\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}$ .

The area (in square inches) of this equilateral triangle will be:

$\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}$ .

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

$\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}$ .

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is $10$ inches, the radius of this circle will also be $10$ inches.

The area (in square inches) of a circle of radius $10$ inches is:

$\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi$ .