Answer:
Aidan is 2 miles far from the ending point when he reaches the water station.
Step-by-step explanation:
The locations of the starting point, water station and ending point are (3, 1), (3, 7) and (3, 9), all expressed in miles. First we determine the distances between starting and ending points and between starting point and water station by the Pythagorean Theorem:
From starting point to ending point:
(Eq. 1)

From starting point to water station:
(Eq. 2)

The distance between the water station and the ending point is:
(Eq. 3)


Hence, Aidan is 2 miles far from the ending point when he reaches the water station.
Answer:

small cups=30
large cups=40
Step-by-step explanation:
let x be the number of small cups and y the number of large cups.
-Given that 10 more cups than small cups of lemonade were sold:

#Before the 10 more were sold, the number of x and y sold were equal>

The number of small cups sold was 30
#Since, the number of large cups was 10 more, y=x+10=30+10=40
Answer:
I think the answer is repeating because it'd be
0.55
Answer:

And for this case we know this condition:

By the complement rule we know that:

But since the distribution is symmetrical we know that:

So then the statement for this case is FALSE.
b. False
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
For this case if we define the random variable of interest X and we know that this random variable follows a normal distribution:

And for this case we know this condition:

By the complement rule we know that:

But since the distribution is symmetrical we know that:

So then the statement for this case is FALSE.
b. False