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sergejj [24]
3 years ago
10

Evalute h^-2 g h=3 g=27

Mathematics
1 answer:
podryga [215]3 years ago
7 0

Applying the definition of negative exponents, we have

3^{-2}\cdot 27 = \dfrac{1}{3^2}\cdot 27 = \dfrac{27}{9} = 3

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