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butalik [34]
3 years ago
6

Which parallelogram will have the smallest area?

Mathematics
2 answers:
Advocard [28]3 years ago
7 0

Answer:

B=7 H=5

Step-by-step explanation:

Hoochie [10]3 years ago
3 0

The last one

Step-by-step explanation:

the one with b=7 & h=5 because you have to multiply both numbers together , so you multiply and then see the smallest answer

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The set of points (-3, 4), (-1, 1), (-3,-2), and (-5,1) identifies the vertices of a quadrilateral. Which is the most specific d
KIM [24]

Answer:

Option (4). Rhombus

Step-by-step explanation:

From the figure attached,

Distance AB = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

                     = \sqrt{(1-4)^2+(-5+3)^2}

                     = \sqrt{(-3)^2+(-2)^2}

                     = \sqrt{13}

Distance BC = \sqrt{(4-1)^2+(-3+1)^2}

                     = \sqrt{9+4}

                     = \sqrt{13}

Distance CD = \sqrt{(-2-1)^2+(-3+1)^2}

                     = \sqrt{9+4}

                     = \sqrt{13}

Distance AD = \sqrt{(1+2)^2+(-5+3)^2}

                     = \sqrt{9+4}

                     = \sqrt{13}

Slope of AB (m_{1}) = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

                           = \frac{4-1}{-3+5}

                           = \frac{3}{2}

Slope of BC (m_{2}) = \frac{4-1}{-3+1}

                            = -\frac{3}{2}

If AB and BC are perpendicular then,

m_{1}\times m_{2}=-1

But it's not true.

[m_{1}\times m_{2}=(\frac{3}{2})(-\frac{3}{2}) = -\frac{9}{4}]

It shows that the consecutive sides of the quadrilateral are not perpendicular.

Therefore, ABCD is neither square nor a rectangle.

Slope of diagonal BD = \frac{4+2}{-3+3}

                                    = Not defined (parallel to y-axis)

Slope of diagonal AC = \frac{1-1}{-1+5}

                                    = 0 [parallel to x-axis]

Therefore, both the diagonals AC and BD will be perpendicular.

And the quadrilateral formed by the given points will be a rhombus.

5 0
3 years ago
Jacob needs to collect at least 120 cans for a food drive to earn community service credit. He has already collected 64 items.
dalvyx [7]

An inequality that represent  the number of cans, c, that Jacob must still collect is  c\geq 56 .

<u>Step-by-step explanation:</u>

Here we have , Jacob needs to collect at least 120 cans for a food drive to earn community service credit. He has already collected 64 items.  We need to solve the following :

<u>Part A: </u>

Write and solve an inequality to represent the number of cans, c, that Jacob must still collect.

Jacob has collected 64 cans . Jacob need to collect at least 120 cans for a food drive to earn community service credit , Let Number of cans that Jacob have to collect is c , So following is the inequality for above scenario:

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⇒ (c+64)-64\geq 120-64

⇒ c\geq 56

Therefore , An inequality that represent  the number of cans, c, that Jacob must still collect is  c\geq 56 .

8 0
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