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Wewaii [24]
4 years ago
10

NEED HELP FAST

Physics
2 answers:
slava [35]4 years ago
8 0

Answer:

The part of the Sun that you are observing is the photosphere . This appearance is called photosphere.

Explanation:

MaRussiya [10]4 years ago
7 0
The answer is Photosphere
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An 80 kg astronaut has gone outside his space capsule to do some repair work. Unfortunately, he forgot to lock his safety tether
Anna [14]

Answer:

the time taken by the astronaut to reach safety = 9.8 hr

Explanation:

The equation for intensity can be written as :

I = \frac{P}{A}

where :

\frac{I}{c}= \frac{F}{A}

Replacing that into the above previous equation; we have:

\frac{P}{Ac}=\frac{F}{A}

F = \frac{P}{c}

However ; the force needed to push the astronaut is as follows:

F = ma

where ;

m = mass of the  astronaut and a = its acceleration

we as well say;

\frac{P}{c} = ma

a = \frac{P}{mc}

Replacing P with 1000 W ; m with 80 kg and 3*10^{8} \  m/s for  c

Then; a = \frac{1000 \ W}{(80)(3.0*10^8)}

a = 4.2*10^{-8} \ m/s

It is also known that the battery will run for one hour and after which the battery on the laser will run out

Then to determine the change in the position after the first hour ; we have:

\Delta x_1 = \frac{1}{2}*4.2*10^{-8} \ m/s^2 ) (1.0 \ h)^2

\Delta x_1 = \frac{1}{2}*4.2*10^{-8} \ m/s^2 ) (1.0 *3600 s)^2

= 0.27 m

Furthermore, the final velocity of the astronaut is determined as:

v_1 = at_1

where ;

v_1 = final \ velocity

replacing t_1 = 1.0 \ h and a =  4.2*10^{-8} \ m/s; Then:

v_1 = (4.2*10^8 \ m/s * 1.0 \ h * \frac{ 3600\ s}{1.0 \ h})

v_1 =  1.51 *10^{-4} \ m/s

Also; when he drifted 5.0 m away from the capsule; the distance is far short of the 5 m but he still have 9 hours left of oxygen . In addition to that, he acceleration is also zero and the final velocity remains the same, so:

To find the final distance traveled by the astronaut ;we have:

\Delta x_2 = d - \Delta x_1

where;

\Delta x_2 = the final distance

d = total distance

So;

\Delta x_2 = 5 m - 0.27 m \\ \\ \Delta x_2 = 4.73 \ m

The time taken to reach the final distance can be calculated as:

t_2 = \frac{\Delta x_2 }{v_1}

where;

t_2 = is the  time to  reach the final distance

Replacing 4.73 for {\Delta x_2 } and  1.51*10^{-4} m/s for v_1

t_2 = \frac{4.73 \ m }{1.51*10^{-4} \ m/s}

t_2 = 31500 \ s (\frac{1.0 \ h}{3600 \ s} )

t_2 = 8.8 \ h

We knew the laser was operated for 1 hour; thus the total time taken by the astronaut to  reach the final distance is the sum of the time taken to reach the final distance and the operated time of the laser.

Hence ; the time taken by the astronaut to reach safety = 9.8 hr

8 0
3 years ago
A 1.0 cm3 air bubble is released from the sandy bottom of a warm, shallow sea, where the gauge pressure is 1.6 atm. The bubble r
Zigmanuir [339]

Answer:

ffgg gwre for rge oooo

Explanation:

ffgggg fdgv sfv

4 0
3 years ago
3. Explain why one side of the single magnet attracted the metal surface, but repelled the stack of magnets
valina [46]

Answer:

Explained

Explanation:

one side of the single magnet attracted the metal surface, but repelled the stack of magnets because  magnet's both poles  try to attract by inducing opposite pole on the metal surface,but the pole closer to the metal is able to induce more magnetic character .so, attractive force due to this is more strong as the distance is also less as compared to the other pole.

7 0
3 years ago
Read 2 more answers
What is the reversal experienced by an image formed in a plane mirror called?
algol [13]

Answer:

Lateral Inversion

Explanation:

lateral inversion simply means the change around of the image of an object from side to side

The image of an object formed by a plane mirror is laterally inverted.

5 0
3 years ago
Where do people and animals get energy to move arond
LuckyWell [14K]
<span>People and animals get energy to move arond in the food they eat.

</span>
6 0
4 years ago
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