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3 years ago

1

Physics

1 answer:

Darina [25.2K]3 years ago

3 0

Answer:

7.5 x 10⁻⁸N

Explanation:

Given parameters:

Mass 1 = 60kg

Mass 2 = 75kg

Distance between the bodies = 2m

Unknown:

Gravitational fore = ?

Solution:

The gravitational force between the two bodies can be derived using;

F = $\frac{G mass 1 x mass 2}{distance^{2} }$

G is the universal gravitation constant = 6.67 x 10⁻¹¹m³kg⁻¹s⁻²

Insert the parameters and solve;

F = $\frac{6.67 x 10^{-11} x 60 x 75}{2^{2} }$ = 7.5 x 10⁻⁸N

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A uniform rod is set up so that it can rotate about a perpendicular axis at one of its ends. The length and mass of the rod are

igor_vitrenko [27]

Answer:

0.231 N

Explanation:

To get from rest to angular speed of 6.37 rad/s within 9.87s, the angular acceleration of the rod must be

$\alpha = \frac{\theta}{t} = \frac{6.37}{9.87} = 0.6454 rad/s^2$

If the rod is rotating about a perpendicular axis at one of its end, then it's momentum inertia must be:

$I = \frac{mL^2}{3} = \frac{1.27*0.847^2}{3} = 0.303kgm^2$

According to Newton 2nd law, the torque required to exert on this rod to achieve such angular acceleration is

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So the force acting on the other end to generate this torque mush be:

$F = \frac{T}{L} = \frac{0.196}{0.847} = 0.231 N$

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4 years ago

Positive ions differ from neutral atoms in that

Katena32 [7]

Answer:

The answer is C.

Explanation:

An ion is unlike a neutral atom in the fact that it has a charge. Because electrons are negatively charged, an atom becomes more positive if electrons are lost.

5 0

3 years ago

In gas chromatography, what are the advantages of (a) temperature programming? (check all that apply.)

TiliK225 [7]

The following statements apply:
1. Resolution of low boiling solutes is maintained.
2. Retention times of high boiling solutes are decreased.
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3 0

3 years ago

in a hydraulic garage the small piston has a radius of 5 cm and the large piston has radius of 15 cm what force must be applied

viktelen [127]

The force applied to small piston = 2.2 x 10³ N

<h3>Further explanation</h3>

Given

a radius of 5 cm and 15 cm

weight 20000 N

Required

Force applied

Solution

Pascal Law :

F₁/A₁=F₂/A₂

A₁ = π.5²

A₂ = π.15²

F₁/ π.5² cm² = 20000/π.15² cm²

F₁ = 2222.22 N⇒2.2 x 10³ N

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3 years ago

The inner and outer surfaces of a cell membrane carry a negative and positive charge respectively. Because of these charges, a p

padilas [110]

Answer:

The magnitude of the electric field inside the membrane is 8.8×10⁶V/m

Explanation:

The electric field due to electric potential at a distance Δs is given by

E=ΔV/Δs

We have to find the magnitude electric field in the membrane

Ecell= -ΔV/Δs

$E_{cell}=-\frac{V_{in}-V_{out}}{s} \\E_{cell}=\frac{V_{out}-V_{in}}{s}\\E_{cell}=\frac{0.070V}{8*10^{-9}m } \\E_{cell}=8.8*10^{6}V/m$

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6 0

3 years ago