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vovikov84 [41]
3 years ago
8

1

Physics
1 answer:
Darina [25.2K]3 years ago
3 0

Answer:

7.5 x 10⁻⁸N

Explanation:

Given parameters:

Mass 1  = 60kg

Mass 2  = 75kg

Distance between the bodies  = 2m

Unknown:

Gravitational fore  = ?

Solution:

The gravitational force between the two bodies can be derived using;

  F  = \frac{G mass 1 x mass 2}{distance^{2} }  

    G is the universal gravitation constant  = 6.67 x 10⁻¹¹m³kg⁻¹s⁻²

Insert the parameters and solve;

  F  = \frac{6.67 x 10^{-11}  x 60 x 75}{2^{2} }   = 7.5 x 10⁻⁸N

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The correct option is;

Amplitude

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16,18,22

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Engineering solutions use scientific laws to predict behaviors of objects in certain situations. Will used Newton's Laws of Moti
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Two charges (q1 = 3.8*10-6C, q2 = 3.2*10-6C) are separated by a distance of d = 3.25 m. Consider q1 to be located at the origin.
Sergio039 [100]

Answer:

The distance is 1.69 m.

Explanation:

Given that,

First charge q_{1}= 3.8\times10^{-6}\ C

Second charge q_{2}=3.2\times10^{-6}\ C

Distance = 3.25 m

We need to calculate the distance

Using formula of electric field

E_{1}=E_{2}

\dfrac{kq_{1}}{x^2}=\dfrac{kq_{2}}{(d-x)^2}

\dfrac{q_{1}}{q_{2}}=\dfrac{(x)^2}{(d-x)^2}

\sqrt{\dfrac{q_{1}}{q_{2}}}=\dfrac{x}{d-x}

x=(d-x)\times\sqrt{\dfrac{q_{1}}{q_{2}}}

Put the value into the formula

x=(3.25-x)\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}

x+x\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}=3.25\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}

x(1+\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}})=3.25\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}

x=\dfrac{3.25\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}}{(1+\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}})}

x=1.69\ m

Hence, The distance is 1.69 m.

5 0
3 years ago
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