1

Physics

1 answer:

Darina [25.2K]3 years ago

3 0

Answer:

7.5 x 10⁻⁸N

Explanation:

Given parameters:

Mass 1 = 60kg

Mass 2 = 75kg

Distance between the bodies = 2m

Unknown:

Gravitational fore = ?

Solution:

The gravitational force between the two bodies can be derived using;

F = $\frac{G mass 1 x mass 2}{distance^{2} }$

G is the universal gravitation constant = 6.67 x 10⁻¹¹m³kg⁻¹s⁻²

Insert the parameters and solve;

F = $\frac{6.67 x 10^{-11} x 60 x 75}{2^{2} }$ = 7.5 x 10⁻⁸N

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With what tension must a rope with length 3.00 mm and mass 0.105 kgkg be stretched for transverse waves of frequency 40.0 HzHz t

VladimirAG [237]

Answer:

the tension of the rope is 34.95 N

Explanation:

Given;

length of the rope, L = 3 m

mass of the rope, m = 0.105 kg

frequency of the wave, f = 40 Hz

wavelength of the wave, λ = 0.79 m

Let the tension of the rope = T

The speed of the wave is given as;

$v = f\lambda = \sqrt{\frac{T}{\mu} } \\\\where;\\\\\mu \ is \ mass \ per \ unit \ length\\\\\mu = \frac{0.105}{3} = 0.035 \ kg/m\\\\v = f\lambda = 40 \times 0.79 = 31.6 \ m/s\\\\v = \sqrt{\frac{T}{\mu} } \\\\v^2 = \frac{T}{\mu} \\\\T = v^2 \mu\\\\T = (31.6^2)(0.035)\\\\T = 34.95 \ N$