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SSSSS [86.1K]
3 years ago
14

Using the rules for significant figures, what do you get when you multiply 67.6 by 1.2?

Physics
2 answers:
Natali [406]3 years ago
5 0

Answer:

B. 81

Explanation:

Answer: = 81  (real number)

Answer:= 8.1 × 101   ( In scientific notation)

Answer:= 8.1e1  (scientific e notation)

Rule: All the number before the power of 10 are considered as significant figures.

number of significant figures: 2

Paul [167]3 years ago
3 0

Answer:

B. 81

Explanation:

When you multiply two numbers, round the answer to the least number of significant figures available.  67.6 has three significant figures, and 1.2 has two significant figures.  So we round to two significant figures.

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5. The value of a car decreases by 15% each
Kazeer [188]

Answer:

the car is worth $2,400

Explanation:

6000*15%=900

900*4=3600

6000-3600=2400

6 0
3 years ago
The speed of an object is given by v = 5.00t^2 + 4.00t where v is in m/s and t is in s. What is the acceleration of the object a
nexus9112 [7]
The speed is 
v = 5t² + 4t
where 
v is in m/s, and t in s.

The acceleration is the derivative of the velocity. It is
a = 10t + 4

When t = 2 s, the acceleration is
a(2) = 10*2 +4 = 24 m/s²

Answer: 24 m/s²
8 0
3 years ago
A bus is designed to draw its power from a rotating flywheel that is brought up to 3000 rpm by an electric motor. The flywheel i
Arada [10]

To solve this problem we will apply the concept of rotational kinetic energy. Once this energy is found we will proceed to find the time from the definition of the power, which indicates the change of energy over time. Let's start with the kinetic energy of the rotating flywheel is

E_r = \frac{1}{2} I\omega^2

Here

I = moment of inertia

\omega = Angular velocity

Here we have that,

\omega = 3000\frac{rev}{min}(\frac{2\pi rad}{1rev})(\frac{1min}{60s})

\omega = 314.159rad/s

Replacing the value of the moment of inertia for this object we have,

E_r = \frac{1}{2} (\frac{MR^2}{2})\omega^2

E_r = \frac{1}{2} (\frac{2000(0.5)^2}{2})(314.159)^2

E_r = 1.233698*10^7J

The expression for average power is

P = \frac{E_r}{\Delta t}

\Delta t = \frac{E_r}{P}

\Delta t = \frac{1.233698*10^7}{20*10^3}

\Delta t = 616.8s \approx 620s

Therefore the correct answer is 620s.

3 0
4 years ago
Is there a pattern to the volcano distribution around the plant?
alexira [117]
Hi there!

Typically volcanoes are found alongside tectonic plate boundaries and in that sense could be considered a pattern. One of the most famous is 'The Ring of Fire' which is a ring of volcanoes in the pacific ocean along the pacific plate boundary.
6 0
3 years ago
A block of mass 4 kg, which has an initialspeed of 3 m/s at timet= 0, slides on ahorizontal surface.Find the magnitude of the wo
Vikki [24]

Answer:

18 J

Explanation:

Work done: This can be defined as the product of force and distance acting on a body. The S. I unit of work is Joules (J)

From the question, the work that must be done in bringing the block to rest is equal to the kinetic energy of the block.

Ek = 1/2mv².................... Equation 1

Where Ek = kinetic eenrgy m = mass of the block, v = velocity of the block.

Given: m = 4 kg, v = 3 m/s.

Substituting into equation 1

Ek = 1/2(4)(3²)

Ek = 2(9)

Ek = 18 J.

Thus the work that must me done on the block to bring it to rest = 18 J.

5 0
4 years ago
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