The frequency is how many per second:
(6 swings)/(30 sec) = (6/30) swing/sec = 0.2 per sec = 0.2 Hz .
The period is how long each one takes, or seconds per swing.
It's exactly the flip of frequency.
So we could just take the frequency, flip it, and find 1 / 0.2 ,
but let's do it the long way:
(30 sec) / (6 swings) = (30/6) sec/swing = 5 seconds .
Answer:
-0.01 mm
Explanation:
We are given that
The value of one division of vernier scale =0.5 mm
The value of one main scale division=0.49 mm
We have to find the value of least count of the instrument in mm.
We know that
Leas count of vernier caliper=1 main scale division-1 vernier scale division
Least count of vernier caliper=0.49-0.50=-0.01 mm
Hence, the least count of the instrument=-0.01 mm
Answer: -0.01 mm
Answer:
C.) The Distance DH = 1.5 lambda
Explanation:
This statement C.) is false, because it does not count as the 1.5 wavelength, it is less than 1 wavelength.
