2s + 36 > 50 do fractional solutions make sense in this context? Why or why not

Mathematics

1 answer:

Arisa [49]4 years ago

6 0

Answer:

There may be fractional solutions in this context.

Step-by-step explanation:

We are given an inequality equation and we have to get a solution to that.

It is, 2s + 36 > 50

⇒ 2s > 50 - 36 {Subtracting 36 from both the sides}

⇒ 2s > 14

⇒ s > 7 {Dividing both sides by 2}

Therefore, solution of this given inequality is s > 7.

Now, the value of s is greater than 7 which may be an integer or a fraction.

So, there may be fractional solutions in this context. (Answer)

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nexus9112 [7]

Answer:

360,360

Step-by-step explanation:

This is called a Permutation with repetition, we want to know in how many ways we can arrange a certain ammount of elements (normal permutation), BUT some of those elements are identical.

The formula we use in these cases is:

$\frac{n!}{n1!*n2!*...*ni!}$

where n is the total amount of elements, n1 is the amount of repeated elements of the type 1, n2 is the amount of repeated elements of the type 2, ni is the amount of repeated elements of the type i.

In this particular case we have:

$n=13$ (total amount of shirts)