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laila [671]
3 years ago
6

In parallelogram LMNO, what is the measure of angle M? 20 60 80 100

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
8 0

Answer:

80

Step-by-step explanation:

180-100=80

erastovalidia [21]3 years ago
4 0

Answer:

80

Step-by-step explanation:

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Use the Ratio Test to determine the convergence or divergence of the series. If the Ratio Test is inconclusive, determine the co
jeka57 [31]

Answer:

<h2>A. The series CONVERGES</h2>

Step-by-step explanation:

If \sum a_n is a series, for the series to converge/diverge according to ratio test, the following conditions must be met.

\lim_{n \to \infty} |\frac{a_n_+_1}{a_n}| = \rho

If \rho < 1, the series converges absolutely

If \rho > 1, the series diverges

If \rho = 1, the test fails.

Given the series \sum\left\ {\infty} \atop {1} \right \frac{n^2}{5^n}

To test for convergence or divergence using ratio test, we will use the condition above.

a_n = \frac{n^2}{5^n} \\a_n_+_1 = \frac{(n+1)^2}{5^{n+1}}

\frac{a_n_+_1}{a_n} =  \frac{{\frac{(n+1)^2}{5^{n+1}}}}{\frac{n^2}{5^n} }\\\\ \frac{a_n_+_1}{a_n} = {{\frac{(n+1)^2}{5^{n+1}} * \frac{5^n}{n^2}\

\frac{a_n_+_1}{a_n} = {{\frac{(n^2+2n+1)}{5^n*5^1}} * \frac{5^n}{n^2}\\

aₙ₊₁/aₙ =

\lim_{n \to \infty} |\frac{ n^2+2n+1}{5n^2}| \\\\Dividing\ through\ by \ n^2\\\\\lim_{n \to \infty} |\frac{ n^2/n^2+2n/n^2+1/n^2}{5n^2/n^2}|\\\\\lim_{n \to \infty} |\frac{1+2/n+1/n^2}{5}|\\\\

note that any constant dividing infinity is equal to zero

|\frac{1+2/\infty+1/\infty^2}{5}|\\\\

\frac{1+0+0}{5}\\ = 1/5

\rho = 1/5

Since The limit of the sequence given is less than 1, hence the series converges.

5 0
3 years ago
What is the perimeter of a quadrilateral with vertices at (3,-6),(8,-6),(3,-4), and (8,-4)
Eduardwww [97]

Answer:

im sorry i dont know but this is for a challenge

Step-by-step explanation:

3 0
2 years ago
Solve for x or find x​
Vanyuwa [196]

Answer:

x = 7

Step-by-step explanation:

Assuming the quadrilateral is a parallelogram, then the diagonals bisect each other.

7x - 8 = 41

7x = 49

x = 7

7 0
3 years ago
Read 2 more answers
Solve the system:<br> 2.5(x−3y)−3=−3x+0.5 3(x+6y)+4=9y+19
Aleksandr-060686 [28]

Answer:

The value of x and y that satisfy the equations is x = 2 and y = 1

Step-by-step explanation:

Given

2.5(x−3y)−3=−3x+0.5

3(x+6y)+4=9y+19

Required.

Find x and y

We start by opening all brackets

2.5(x−3y)−3=−3x+0.5 becomes

2.5x - 7.5y - 3 = -3x + 0.5

Collect like terms

2.5x + 3x - 7.5y = 3 + 0.5

5.5x - 7.5y = 3.5 ---- Equation 1

In similar vein, 3(x+6y)+4=9y+19 becomes

3x + 18y + 4 = 9y + 19

Collect like terms

3x + 18y - 9y = 19 - 4

3x + 9y = 15

Multiply through by ⅓

⅓ * 3x + ⅓ * 9y = ⅓ * 15

x + 3y = 5

Make x the subject of formula

x = 5 - 3y

Substitute 5 - 3y for x in equation 1

5.5(5 - 3y) - 7.5y = 3.5

27.5 - 16.5y - 7.5y = 3.5

27.5 - 24y = 3.5

Collect like terms

-24y = 3.5 - 27.5

-24y = -24

Divide through by - 24

y = 1

Recall that x = 5 - 3y.

Substitute 1 for y in this equation

x = 5 - 3(1)

x = 5 - 3

x = 2

Hence, x = 2 and y = 1

3 0
3 years ago
Solve the equation on the interval [0,2π). 7 sec x-7=0, x=?
Oksanka [162]

\huge \bf༆ Answer ༄

Let's solve ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:7 \sec(x)  - 7 = 0

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:7 \sec(x)  = 7

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \sec(x)  = 7 \div 7

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \sec(x)  = 1

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 0

8 0
2 years ago
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