Question

Someone solve for me please WILL MARK THE BRAINLIEST FOR EXPLANATION !!!!!

Answer 1

Answer:

$\frac{(2n+5)(7n+3)}{2n(2n+3)(5n-1)}$

Step-by-step explanation:

At first we simplify each fraction

$\frac{10n^{2}+23n-5 }{4n^{2}+6n}=\frac{(5n-1)(2n+5)}{2n(2n+3)}$

$\frac{25n^{2}-10n+1}{7n+3}=\frac{(5n-1)(5n-1)}{7n+3}$

We will reverse the fraction after the division sign and change the division sign to multiplication sign

$\frac{(5n-1)(2n+5)}{2n(2n+3)}$ × $\frac{(7n+3)}{(5n-1)(5n-1)}$

Simplify the two fractions

$\frac{(2n+5)(7n+3)}{2n(2n+3)(5n-1)}$⇒Simplest form