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3 years ago

Shila read the

Mathematics

1 answer:

MrRa [10]3 years ago

5 0

Answer: Primary data

Step-by-step explanation: Primary data is information collected through original or first-hand research. Since Shila is figuring out the temperature herself, it is primary data.

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creativ13 [48]

Let x represent the worth of the professional basketball player's autograph a year ago. Since his autograph's worth increased by 40% now, $364 is 1.40x.

364 = 1.40x

Solving for x gives x = 260.

Thus, the autograph of the basketball player was worth only $260 last year.

4 0

3 years ago

Please help!!!!! 10 points!!

IrinaK [193]

Answer:

Both calculated the slope as 1/3

Step-by-step explanation:

Avis:

Rise = 4

Run = 12

Rise goes over the run: 4/12

4/12 simplifies into 1/3

Alec:

Rise= 2

Run= 6

Rise goes over the run: 2/6

2/6 simplifies into 1/3

4 0

3 years ago

Read 2 more answers

Pls help! will give brainlist!

lara31 [8.8K]

It couldn’t be anything else but C line reflection i’m assuming

4 0

3 years ago

Read 2 more answers

At a dinner, the meal cost $32 and a sales tax of $1.87 was added to the bill. How much would the sales tax be on a $64 meal?

Vilka [71]

Answer:

3.74

Step-by-step explanation:

Since 64 is x2 the number 32, and the tax for that is 1.87 you times that times 2 so:

1.87x2=3.74

3 0

2 years ago

A soccer ball is kicked from 3 feet above the ground. the height,h, in feet of the ball after t seconds is given by the function

dexar [7]

Here's our equation.

$h=-16t+64t+3$

We want to find out when it returns to ground level (h = 0)

To find this out, we can plug in 0 and solve for t.

$0 = -16t+64t+3 \\ 16t-64t-3=0 \\ use\ the\ quadratic\ formula\ \frac{-b\±\sqrt{b^2-4ac}}{2a} \\ \frac{-(-64)\±\sqrt{(-64)^2-4(16)(-3)}}{2*16} = \frac{64\±\sqrt{4096+192}}{32}$

$= \frac{64\±\sqrt{4288}}{32} = \frac{64\±8\sqrt{67}}{32} = \frac{8\±\sqrt{67}}{4} = \boxed{\frac{8+\sqrt{67}}{4}\ or\ 2-\frac{\sqrt{67}}{4}}$

So the ball will return to the ground at the positive value of $\boxed{\frac{8+\sqrt{67}}{4}}$ seconds.

What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!

$\frac{1}2(\frac{8+\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(2+\frac{\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(4) = 2$

$h=-16t^2+64t+3 \\ h=-16(2)^2+64(2)+3 \\ \boxed{h=67}$

8 0

3 years ago