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2 years ago

Solve 3x-18=2y and 5x-6y=14 by elimination or substitution . SHOW ALL WORK!!!

Mathematics

1 answer:

Nataly_w [17]2 years ago

5 0

Answer:

3x - 18 = 2y

5x - 6y = 14

5x - 3*(2y) = 14

5x - 3*(3x - 18) = 14

5x - 9x + 54 = 14

-4x = -40

x = 10

3*10 - 18 = 2y

30 - 18 = 2y

12 = 2y

y = 6

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Chin canned a number of quart jars anf a number of pints jars of tomatoes from hid garden. A pint is 16 onces and a quart is 32

ryzh [129]

Answer:

The equation which models the scenario is: 16 p + 32 q = 1280

Step-by-step explanation:

The total number of pints packed = p

The total number of quarts packed = q

The weight of 1 pint jar of tomatoes = 16 oz

So, the total weight of p pints = p x ( Weight of 1 pint) = p x ( 16 oz) = 16 p

The weight of 1 quart jar of tomatoes = 32 oz

So, the total weight of q quarts = q x ( Weight of 1 quart) = q x ( 32 oz)

= 32 q

Now, the TOTAL WEIGHT of p pints and q quarts

= Total weight of { p pints + q quarts} = 16 p + 32 q

Also, chin canned a total of 1280 ounces.

⇒ TOTAL WEIGHT of p pints and q quarts = 1280 ounces

or, 16 p + 32 q = 1280 ounces

Hence, equation which models the scenario is: 16 p + 32 q = 1280

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3 years ago

Abigail shows up at a restaurant that has 30 tables 12 of them are booth and 18 of them are tables with chairs what is the proba

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What is the height of the trapezoid?

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Answer:

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(x-1)³ find derivative using definition

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Step-by-step explanation:

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Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)

Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

$x^{2} +y^{2}+4x-1=0$

Step-by-step explanation:

Explanation:-

Step 1:-

The equation of the circle having center and radius is

$(x-h)^2+(y-k)^2=r^2$

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

$(\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2} )$

$(-2,0)$

therefore center (h,k) = (-2,0)

Step 2:-

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

$\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}$

$r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}$

$r=\sqrt{5}$

Step 3:-

center (h,k) = (-2,0) and

radius $r=\sqrt{5}$

The standard form of circle equation

$(x-h)^2+(y-k)^2=r^2$

$(x-(-2))^2+(y-0)^2=\sqrt{5} ^2$

on simplification is

$x^{2} +y^{2}+4 x-1=0$

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2 years ago