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jeka94
3 years ago
7

WHat is the ellimination of x-y=-2 and 7x+2y=-5

Mathematics
1 answer:
nydimaria [60]3 years ago
3 0
<span>This question is from textbook
</span><span>1. Solve by substitution or elimination method: 3x – 2y = 26 -7x + 3y = -49 Eliminate x: 3x – 2y = 26 -7x + 3y = -49 the coefficients of x are 3 and -7. Ignoring signs temporarily they are 3 and 7. The least common multiple of 3 and 7 is 21. If we multiply the first equation through by 7, there will be a 21x where the 3x is now. If we multiply the second equation by 3, there will be a -21x where the -7x is. And 21x and -21x will cancel out when we add equals to equals. So let's multiply the first equation through by 7 and the second equation through by 3: 7[ 3x – 2y = 26] 3[-7x + 3y = -49] 21x - 14y = 182 -21x + 9y = -147 Draw a line underneath and add equals to equals vertically: 21x - 14y = 182 -21x + 9y = -147 ------------------- 0x - 5y = 35 -5y = 35 Divide both sides by -5 y = -7 Eliminate y: 3x – 2y = 26 -7x + 3y = -49 the coefficients of y are -2 and 3. Ignoring signs temporarily they are 2 and 3. The least common multiple of 2 and 3 is 6. If we multiply the first equation through by 3, there will be a -6y where the -2y is now. If we multiply the second equation by 2, there will be a 6y where the 3y is. And -6y and 6y will cancel out when we add equals to equals. So let's multiply the first equation through by 3 and the second equation through by 2: 3[ 3x – 2y = 26] 2[-7x + 3y = -49] 9x - 6y = 78 -14x + 6y = -98 Draw a line underneath and add equals to equals vertically: 9x - 6y = 78 -14x + 6y = -98 ------------------- -5x + 0y = -20 -5x = -20 Divide both sides by -5 x = 4 So the solution is (x,y) = (4,-7) ==================================== 2. Solve by substitution or elimination method: 4x – 5y = 14 -12x + 15y = -42 Eliminate x: 4x – 5y = 14 -12x + 15y = -42 The coefficients of x are 4 and -12 Ignoring signs temporarily they are 4 and 12. The least common multiple of 4 and 12 is 12. If we multiply the first equation through by 3, there will be a 12x where the 4x is now. We don't need to do anything to the second equation for the 12x and the -12x will cancel out when we add equals to equals. So let's multiply the first equation through by 7 and leave the second equation as it is: 3[ 4x – 5y = 14] -12x + 15y = -42 12x - 15y = 42 -12x + 15y = -42 Draw a line underneath and add equals to equals vertically: 12x - 15y = 42 -12x + 15y = -42 ------------------- 0x + 0y = 0 As you can see, any number may be substituted for x and y and that will always be true, since you'll always get 0 on the left and that will always give 0 and 0 will always equal to 0. So there are infinitely many solutions. This sort of system is called "dependent". We need go no further. We just state that the system is dependent and has INFINITELY MANY solutions. =============================================== 3. Solve by substitution or elimination method: -2x + 6y = 1 10x – 30y = -15 Eliminate x: -2x + 6y = 1 10x – 30y = -15 The coefficients of x are -2 and -10 Ignoring signs temporarily they are 2 and 10. The least common multiple of 2 and 10 is 10. If we multiply the first equation through by 5, there will be a -10x where the -2x is now. We don't need to do anything to the second equation for the 10x and the -10x will cancel out when we add equals to equals. So let's multiply the first equation through by 5 and leave the second equation as it is: 5[ -2x + 6y = 1] 10x - 30y = -15 -10x + 30y = 5 10x - 30y = -15 Draw a line underneath and add equals to equals vertically: -10x + 30y = 5 10x - 30y = -15 ------------------- 0x + 0y = -10 </span>
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Solving systems of equations using substitution p=q+2<br> 4p+3q= -27
GREYUIT [131]
Ok, so you are given the value of P=q+2

The substitution method tells us that we must insert the value we know, into the second equation, 4P+3q= -27


Doing so will give us 4(q+2)+3q= -27

For right now, lets just focus on the first part, 4(q+2)

We can simplify this by distributing(multiplying) the 4 to whats inside the variables.

This will give us 4q+8

now lets add this back to the rest of the equation >>>  4q+8+3q = -27

We can further simplify by adding like terms >>> 7q+8 = -27

subtract the 8 from both sides >>> 7q = -35

now divide both sides by 7 >>> q = -35/7

Therefor q = -5

EDIT* 

now that we know q = -5 we can put q into the equation for P !

we know that p=q+2

so lets put q in now >>> p=(-5)+2

and simplify>>> p = -3

I hope this helps:)
6 0
3 years ago
Still I need sleep...
Pani-rosa [81]

Answer:

d) 28.472

Step-by-step explanation:

you need to find the length of all the outside edges. for the triangles you will need to use the pythagorean theorem

4 0
3 years ago
Between which two numbers on the number line is B?
Vanyuwa [196]

Answer:

C. Between 4 and 5.......

6 0
2 years ago
Read 2 more answers
Explain how you can use base ten blocks to find 1.54+ 2.37
solong [7]
0.00

*First column to your left - ones column (1)
*Column just after decimal place, in the middle - tenths column (1/10)
*Column to the far right - hundredths column (1/100)

The only numbers that can go in these columns are 0-9.

-------------

1.54 + 2.37 

= (1 + 5/10 + 4/100) + (2 + 3/10 + 7/100)

= 1 + 5/10 + 4/100 + 2 + 3/10 + 7/100

= 3 + 8/10 + 11/100

= 3 + 8/10 + (10/100 + 1/100)

= 3 + 8/10 + (1/10 + 1/100)

= 3 + 8/10 + 1/10 + 1/100

= 3 + 9/10 + 1/100

= 3.91
6 0
3 years ago
doing all 4 would help but you don't have to do all of them 2 or one is fine with me. but no fake answers
Oduvanchick [21]

Answer:

the picture is kinda blur but nvm

Step-by-step explanation:

3:b

4:b

5:a

6:b

4 0
3 years ago
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