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3 years ago

Water lilies are often used to decorate ponds, as shown in the photo. But they are also famous for their unusual growth pattern!

2 answers:

5 0

There really isn't a right or wrong answer since this is a prediction but to solve this look at the graph and try to see the pattern

Mademuasel [1]3 years ago

3 0

Answer: its 79 lilies at 30 days..

Step-by-step explanation:

im on e2020

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What are the missing numbers in the data set? Assume the numbers are in order

prohojiy [21]

Answer:

This answer is 42

Step-by-step explanation:

42 - 24 = 18

6 0

3 years ago

Each person in ellens family drinks 8 1/3 ounces of water. If 5 people are in ellen's family. how many ounces of water do they d

Svetach [21]

Answer:

41 2/3 oz of water

Step-by-step explanation:

All you have to do is multiply 8 1/3 by 5.

First, lets convert 8 1/3 into an improper fraction (a fraction where the numerator is greater than the denominator):

8 1/3 = 25/3

now, we can multiply 25/3 by 5 and get 125/3, which simplifies to 41 2/3

5 0

3 years ago

PLEASE HELP ME....ASAP

olchik [2.2K]

Answer:

1681 for area of <em>rectangle</em>

7 0

3 years ago

I need help lol. please give me an explaination as well ty <3

Feliz [49]

You need to write it out such as number 8 would be 10x10x10x10 so for every number on top you multiply the number by itself

3 0

3 years ago

Sulfur compounds cause "off-odors" in wine, so winemakers want to know the odor threshold, the lowest concentration of a compoun

aev [14]

Answer:

a) $29.4-1.96\frac{7}{\sqrt{10}}=25.06$

$29.4+1.96\frac{7}{\sqrt{10}}=33.74$

So on this case the 95% confidence interval would be given by (25.06;33.74)

b) $z=\frac{29,4-25}{\frac{7}{\sqrt{10}}}=1.988$

$p_v =P(z>1.988)=0.0234$

If we compare the p value and the significance level given $\alpha=Step-by-step explanation:Previous conceptsA confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval". 
The margin of error is the range of values below and above the sample statistic in a confidence interval. 
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean". 
Part a
Data given: 30 30 42 35 22 33 31 29 19 23
We can calculate the sample mean with the following formula:[tex] \bar X = \frac{\sum_{i=1}^n X_i}{n}= 29.4$ the sample mean

$\mu$ population mean (variable of interest)

$\sigma=7$ represent the population standard deviation

n=10 represent the sample size

95% confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$29.4-1.96\frac{7}{\sqrt{10}}=25.06$

$29.4+1.96\frac{7}{\sqrt{10}}=33.74$

So on this case the 95% confidence interval would be given by (25.06;33.74)

Part b

What are H0 and Ha for this study?

Null hypothesis: $\mu \leq 25$

Alternative hypothesis : $\mu>25$

Compute the test statistic

The statistic for this case is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$z=\frac{29,4-25}{\frac{7}{\sqrt{10}}}=1.988$

Give the appropriate conclusion for the test

Since is a one side right tailed test the p value would be:

$p_v =P(z>1.988)=0.0234$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

8 0

3 years ago