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oksano4ka [1.4K]
3 years ago
8

A space shuttle orbits earth at a rate of about 4,375 miles in 15 minutes. At the rate, how far does the space shuttle travel ar

ound earth in 1 hour?
Mathematics
2 answers:
ludmilkaskok [199]3 years ago
6 0
4,375*4=17500


Hope this helps
siniylev [52]3 years ago
6 0
First you would divide 4,375 by 15 and will get 291.6

There min in and 1hour so
291.6 times 60= 17,596

The shuttle will go 17,596 miles in an hour.
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<h2><u>Answer with explanation</u>:</h2>

Let \mu be the average life of light bulbs.

As per given , we have

Null hypothesis : H_0 : \mu =5400

Alternative hypothesis : H_a : \mu >5400

Since H_a is right-tailed and population standard deviation is also known, so we perform right-tailed z-test.

Formula for Test statistic : z=\dfrac{\overlien{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

where, n= sample size

\overline{x}= sample mean

\mu= Population mean

\sigma=population standard deviation

For n=95,\ \overline{x}=5483\ \&\ \sigma=500, we have

z=\dfrac{5483-5400}{\dfrac{500}{\sqrt{95}}}=1.61796786124\approx1.6180

Using z-value table , Critical one-tailed test value for 0.06 significance level :

z_{0.06}=1.5548

 Decision : Since critical z value (1.5548) < test statistic (1.6180), so we reject the null hypothesis .

[We reject the null hypothesis when critical value is less than the test statistic value .]

Conclusion : We have enough evidence at 0.06 significance level to support the claim that the new filament yields a longer bulb life

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3 years ago
When the sum of 5 and three times a positive number is subtracted from the square of the number, 0 results. Find the number.
Juliette [100K]
x-the\ number\\\\x^2-(5+3x)=0\\\\x^2-5-3x=0\\\\x^2-3x-5=0

Use\ the\ quadratic\ formula:\\a^2x+bx+c=0\\\\\Delta=b^2-4ac\\\\if\ \Delta > 0\ then\ x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\if\ \Delta=0\ then\ x_0=\dfrac{-b}{2a}\\\\if\ \Delta < 0\ then\ no\ solution

x^2-3x-5=0\\\\a=1;\ b=-3;\ c=-5\\\\\Delta=(-3)^2-4\cdot1\cdot(-5)+3+20=29 \ \textgreater \  0\\\\\sqrt\Delta=\sqrt{29}\\\\x_1=\dfrac{3-\sqrt{29}}{2\cdot1}=\dfrac{3-\sqrt{29}}{2} \ \textless \  0\\\\x_2=\dfrac{3+\sqrt{29}}{2\cdot1}=\dfrac{3+\sqrt{29}}{2} \ \textgreater \  0

Answer:\ \boxed{x=\dfrac{3+\sqrt{29}}{2}}
6 0
3 years ago
I don’t understand stand this question someone please help me with work shown
djyliett [7]

Answer:

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please look into the solution down here.

Step-by-step explanation:

since BD bisects it, then the angles should be bisected symmetrically, or in other words, ANGLE ABD = angle DBC,

hence,

4x = 2x +30

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therefore, angle DBC = 2x + 30 = 2(15) + 30 = 60°.

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Answer:

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Step-by-step explanation:

24-5=19

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