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Answer: The choice will be any equation where the slope is the same and the y-intercept is different.
Step-by-step explanation: Using slope-intercept form, y = mx + b,
m is the slope, b is the y-intercept.
Parallel lines will have the same slope.
So, you are looking for another equation that has 5/6 as the coefficient of x.
It could be an equation in the form 6y + 5x = _b_ where the constant, b, could be anything except -42, as that would be an identical line, not parallel.
The squares are shown in the attached picture.
As you can see, JC is half the diagonal of ABCD and JH is half the diagonal of EFGH.
In order to find the area of the shaded figure, we need to subtract the area of the white square (EFGH) from the area of the big square (ABCD).
The area of a square know the diagonal is given by the formula:
A = d² ÷ 2
A(ABCD) = (2×JC)² ÷ 2
= (2×9)² ÷ 2
= 162 cm²
A(EFGH) = (2×JH)² ÷ 2
= (2×4)² ÷ 2
= 32 cm²
Therefore:
A = A(ABCD) - <span>A(EFGH)
= 162 - 32
= 130 cm</span>²
The area of the shaded region is 130 cm².
As you can see, JC is half the diagonal of ABCD and JH is half the diagonal of EFGH.
In order to find the area of the shaded figure, we need to subtract the area of the white square (EFGH) from the area of the big square (ABCD).
The area of a square know the diagonal is given by the formula:
A = d² ÷ 2
A(ABCD) = (2×JC)² ÷ 2
= (2×9)² ÷ 2
= 162 cm²
A(EFGH) = (2×JH)² ÷ 2
= (2×4)² ÷ 2
= 32 cm²
Therefore:
A = A(ABCD) - <span>A(EFGH)
= 162 - 32
= 130 cm</span>²
The area of the shaded region is 130 cm².