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3 years ago

8

dale is trying to find the height of a triangular wall. he already knows the area and the base measurement of the wall. which is

an equation of the area of a triangle, written in terms of the height.

1 answer:

dlinn [17]3 years ago

3 0

A= 1/2 bh
2A/b=h
just solve the original formula in terms of the height

Hope this helps

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Can someone tell me the answer pls

andrey2020 [161]

Answer: The second and the last answer are correct

Step-by-step explanation:

4 0

2 years ago

Divide 240g in the ratio 5:3:4

Nastasia [14]

Answer:

240g in the ratio of 5:3:4

So we need to divide it evenly.

First add up all the ratios.
5+3+4= 12

Now divide 240 by the sum.

240/ 12 = 20

Now you multiply that into each ratio.

5*20 = 100

3*20 = 60

4*20 = 80
Now put it back in the ratio with the new numbers int he exact order as before.

Final Answer: 100 : 60 : 80

Check:

You can check by adding them all up to see if they all go into 240 OR you can divide them each by the number originaly given and you should get 20.

100 + 60 + 80 = 240

100 / 5 = 20

60/3 = 20

80/4 = 20

5 0

2 years ago

Read 2 more answers

Suppose T is a transformation from ℝ2 to ℝ2. Find the matrix A that induces T if T is reflection over the line y=1/2x

trapecia [35]

Answer:

$A = \left[\begin{array}{cc}1&\frac{4}{5}\\\frac{4}{3}&-\frac{3}{5}\end{array}\right]$

Step-by-step explanation:

We have to see how the canonical vectors are transformed throught T. Lets first define T in any basis.

Since T is a reflection, then any element of the line y = x/2 if fixed by T. Therefore T(2,1) = (2,1).

On the other hand, any vector perpendicular to the line direction should be sent to its opposite value. We can take, for example, (-1,2) (note that the scalar product (2,1) * (-1,2) = -2+2 = 0). As a consecuence T(-1,2) = (1,-2). We have

T(2,1) = (2,1)
T(-1,2) = (1,-2)

By summing the first vector with the double of the second one we get, using linearity

T(0,5) = T( (2,1) + 2(-1,2)) = T(2,1) + 2T(-1,2) = (2,1) + 2(1,-2) = (4,-3)

Hence, T(0,1) = (4/5,-3/5)

Now, we take the second vector and substract it the double of the first one (to kill the second variable)

T(-3,0) = T( (-1,2) - 2*(2,1) ) = T(-1,2) -2T(2,1) = (1,-2)-2(2,1) = (-3,-4)

Therefore, T(1,0) = (1,4/3)

The matrix A induced by T has in its first column T(1,0) and in its second column T(0,1). We conclude that

$A = \left[\begin{array}{cc}1&\frac{4}{5}\\\frac{4}{3}&-\frac{3}{5}\end{array}\right]$

3 0

3 years ago

Which of the following is an ordered pair on the graph? What does it represent in this situation?

denis23 [38]

The answer is C I think try putting that one ok I tried to help so yeah um have a great day

8 0

3 years ago

A closed cylindrical can of fixed volume V has radius r.a) Find the surface area, S, as a function of r.b) What happens to the v

andrey2020 [161]

Answer:

Step-by-step explanation:

This question is incomplete; here is the complete question.

A closed cylindrical can of fixed volume V has radius r. (a) Find the surface area, S, as a function of r. (b) What happens to the value of S approaches to infinity? (c) Sketch a graph of S against r, if V=10 cm³.

A closed cylindrical can of volume V is having radius r and height h.

a). Surface area of a cylinder is given by

S = 2(Area of the circular sides) + Lateral area of the can

S = 2πr² + 2πrh

S = 2πr(r + h)

b). Since surface area is directly proportional to radius of the can

S ∝ r

Therefore, when r approaches to infinity (r → ∞)

c). If V = 10 cm³ Then we have to graph S against r.

From the formula V = πr²h

10 = πr²h

h = $\frac{10}{\pi r^{2}}$

By placing the value of h in the formula of surface area,

S = $2\pi r(r+\frac{10}{\pi r^{2}})$

Now we can get the points to plot the graph,

r -2 -1 0 1 2

S -13.72 -13.72 0 26.28 35.13

7 0

3 years ago