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katen-ka-za [31]
3 years ago
12

Determine whether the vectors u and v are parallel, orthogonal, or neither.

Mathematics
1 answer:
Natalija [7]3 years ago
4 0
\mathbf u\cdot\mathbf v=\|\mathbf u\|\|\mathbf v\|\cos\theta

where \theta is the angle between the vectors. You have

10\times9+6\times5=\sqrt{10^2+6^2}\sqrt{9^2+5^2}\cos\theta\iff \cos\theta=\dfrac{30}{\sqrt{901}}\implies \theta\approx1.909^\circ

The vectors would be orthogonal if the dot product had been zero, but that's clearly not the case.

They would be parallel if the angle turned out to be 0^\circ or 180^\circ, but that's also not the case.

So the answer is neither.
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write a multiplication equation that can help you solve for the division equation 48 ÷ 8 = ________. What is the quotient?
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Answer:

6

Step-by-step explanation:

If you're going by 8, subtract 8 from 48, and divide 40/8

That would get you 5. So the next number would be 6

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The radius of a cylinder is measured in meters what unit will the surface area be measured in
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<h3>Answer: A) Square meters</h3>

Explanation:

Imagine that a parent bought a basketball for their son or daughter. If they wrapped the ball with wrapping paper, then that wrapping paper can be unwrapped to form a flat sheet. So the area of the sheet corresponds directly to the surface area. If the sheet is say 1 meter by 1 meter, then the area is 1*1 = 1 square meter. We can abbreviate "square meters" into "meter^2" or "m^2".

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Step-by-step explanation:

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The altitude of a triangle is increasing at a rate of 1 cm/min while the area of the triangle is increasing at a rate of 2 cm2/m
Mnenie [13.5K]

Answer:

The base is reducing at a rate of 3.4cm per min.

Step-by-step explanation:

Let The Height of the Triangle, h

Area of the triangle = A

Area of a Triangle, A= \frac{1}{2}bh

When A=190 cm^2, h=10cm

190= \frac{1}{2}*b*10\\b=38cm

\frac{dA}{dt}=\frac{1}{2}h\frac{db}{dt}+ \frac{1}{2}b\frac{dh}{dt}\\\frac{dh}{dt}=1 cm/min, \frac{dA}{dt}=2cm^2/min,

2=\frac{1}{2}*10*\frac{db}{dt}+ \frac{1}{2}*38*1\\2=5\frac{db}{dt}+19\\2-19=5\frac{db}{dt}\\-17=5\frac{db}{dt}\\\frac{db}{dt}=-\frac{17}{5} =-3.4 cm/min

The base is reducing at a rate of 3.4cm per min.

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3 years ago
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