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2 years ago

What is the minimum amount of saran wrap that Tyler will need to cover the pencil holder, to ensure that no sand leaks out? *

Mathematics

1 answer:

liberstina [14]2 years ago

7 0

Answer:

Step-by-step explanation:

To find the surface area of the triangular prism, you need to find the area of all the sides and add them together. The two triangular bases have already been established to have an area of 3 square units each, so together they have an area of 6 units. Two of the rectangular sides have dimensions of 3.5 by 2.5 units, while one has dimensions 3.5 by 3 units. Adding all of this together, you get a total of 34 square inches, or option e. Hope this helps!

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PLEASE HELP DUE SOON MORE POINTS IF CORRECT!!

SVETLANKA909090 [29]

Answer:

y=4x+35

Step-by-step explanation:

5 0

1 year ago

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Solve y ' ' + 4 y = 0 , y ( 0 ) = 2 , y ' ( 0 ) = 2 The resulting oscillation will have Amplitude: Period: If your solution is A

Vlad [161]

Answer:

$y(x)=sin(2x)+2cos(2x)$

Step-by-step explanation:

$y''+4y=0$

This is a homogeneous linear equation. So, assume a solution will be proportional to:

$e^{\lambda x} \\\\for\hspace{3}some\hspace{3}constant\hspace{3}\lambda$

Now, substitute $y(x)=e^{\lambda x}$ into the differential equation:

$\frac{d^2}{dx^2} (e^{\lambda x} ) +4e^{\lambda x} =0$

Using the characteristic equation:

$\lambda ^2 e^{\lambda x} + 4e^{\lambda x} =0$

Factor out $e^{\lambda x}$

$e^{\lambda x}(\lambda ^2 +4) =0$

Where:

$e^{\lambda x} \neq 0\\\\for\hspace{3}any\hspace{3}\lambda$

Therefore the zeros must come from the polynomial:

$\lambda^2+4 =0$

Solving for $\lambda$ :

$\lambda =\pm2i$

These roots give the next solutions:

$y_1(x)=c_1 e^{2ix} \\\\and\\\\y_2(x)=c_2 e^{-2ix}$

Where $c_1$ and $c_2$ are arbitrary constants. Now, the general solution is the sum of the previous solutions:

$y(x)=c_1 e^{2ix} +c_2 e^{-2ix}$

Using Euler's identity:

$e^{\alpha +i\beta} =e^{\alpha} cos(\beta)+ie^{\alpha} sin(\beta)$

$y(x)=c_1 (cos(2x)+isin(2x))+c_2(cos(2x)-isin(2x))\\\\Regroup\\\\y(x)=(c_1+c_2)cos(2x) +i(c_1-c_2)sin(2x)\\$

Redefine:

$i(c_1-c_2)=c_1\\\\c_1+c_2=c_2$

Since these are arbitrary constants

$y(x)=c_1sin(2x)+c_2cos(2x)$

Now, let's find its derivative in order to find $c_1$ and $c_2$

$y'(x)=2c_1 cos(2x)-2c_2sin(2x)$

Evaluating $y(0)=2$ :

$y(0)=2=c_1sin(0)+c_2cos(0)\\\\2=c_2$

Evaluating $y'(0)=2$ :

$y'(0)=2=2c_1cos(0)-2c_2sin(0)\\\\2=2c_1\\\\c_1=1$

Finally, the solution is given by:

$y(x)=sin(2x)+2cos(2x)$

5 0

2 years ago

A package of four bottles of a sports drink cost $5.28. what is the cost per bottle

Dafna1 [17]

$1.32 per bottle because you would divide $5.28 into 4 and get $1.32

3 0

2 years ago

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What is the equation of the line that passes through (4,3) and (-4,-1)?

german

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 4 &,& 3~) 
% (c,d)
&&(~ -4 &,& -1~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-3}{-4-4}\implies \cfrac{-4}{-8}\implies \cfrac{1}{2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-3=\cfrac{1}{2}(x-4)
\\\\\\
y-3=\cfrac{1}{2}x-2\implies y=\cfrac{1}{2}x+1$

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2 years ago

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____ [38]

Answer:

4.7 · 10^7

Step-by-step explanation:

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2 years ago