A student wants to construct the inscribed circle of a triangle. What is the first step she should take?

Mathematics

2 answers:

Debora [2.8K]2 years ago

7 0

Answer: i think it’s b

Step-by-step explanation:

Leviafan [203]2 years ago

4 0

D) construction of the angle bisector.
So if you have a triangle that is not equilateral the perpendicular bisectors would not work so you need angle bisectors.
I have drawn a diagram
The green is the angle bisectors and the yellow the perpendicular bisectors.
You can see the problem straight away

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Select all irrational numbers.

Maurinko [17]

Answer:

OPTION A

OPTION B

OPTION C

Step-by-step explanation:

Irrational numbers are the subset of real numbers. Their decimal representation neither form a pattern nor terminate.

OPTION A: $\sqrt{\frac{1}{2}}$

This is equal to $\frac{1}{\sqrt{2}}$ .

$\sqrt{2} = 1.414...$ is non-terminating. So, it is an irrational number. Hence, the reciprocal of an irrational number would also be irrational. So, OPTION A is irrational.

OPTION B: $\sqrt{\frac{1}{8}}$

This is equal to $\frac{1}{2\sqrt{2}}$ . Using the same logic as Option A, we regard OPTION B to be irrational as well.

OPTION C: $\sqrt{\frac{1}{10}}$

This is equal to $\frac{1}{\sqrt{5}\sqrt{2}}$ .

Both $\sqrt{5}$ and $\sqrt{2}$ are irrational. So, the product and the reciprocal of the product is irrational as well. So, OPTION C is an irrational number.

OPTION D: $\sqrt{\frac{1}{16}}$

16 is a perfect square and is a rational number. $\frac{1}{\sqrt{16}}$ = $\frac{1}{4}$ . This is equal to 0.25, a terminating decimal. So, OPTION D is a rational number.