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3 years ago

If -10 is subtracted from a number, the result is 6.

Mathematics

2 answers:

vredina [299]3 years ago

6 0

The answer is A -16

grandymaker [24]3 years ago

5 0

Answer:

B.) -4

Step-by-step explanation:

-4-(-10)

-4+10

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9 hundred thousands equal how many tens

il63 [147K]

900,000=10*90,000

So there are 90,000 tens in 900,000.

5 0

3 years ago

Read 2 more answers

Any help would be great

nadya68 [22]

Answer:

Step-by-step explanation:

38=10+13+c

c=38-10-13=15

Hope this helps!

8 0

3 years ago

Triangle ABCis rotated 90° clockwise around the origin to get

Elanso [62]

Answer:

The distance A’C’ is 4.47 units

Step-by-step explanation:

Before we go on, we need to get the appropriate transformation

Mathematically, we have a 90 degrees clockwise rotation yielding the following;

(x,y) to (-y,x)

A is (-4,1)

C is (-2,5)

By transforming, we have

A’( -1,-4)

C’ (-5,-2)

To get the magnitude of the line segment, we are going to use the distance formula between points

We have this as;

D = √(x2-x1)^2 + (y2-y1)^2

D = √(-5-(-1))^2 + (-2-(-4))^2

D = √(-4)^2 + (2)^2

D = √(16 + 4)

D = √20

D = 4.47 units

7 0

3 years ago

Please help me, very important 20 points!

kipiarov [429]

x=96

all interior angles equal 180

Subtract exterior andgles by 180 to get interior angles because they are supplementary

180-134=46

180-130=50

Get the third angle inside the triangle

180-50-46=84

subtract by 180 to get x because they are supplementary

180-84=96

Therefore x =96

4 0

3 years ago

Two points in the Cartesian plane are A(2.00 m, −4.00 m) and B(−3.00 m, 3.00 m). Find the distance between them and their polar

Brrunno [24]

The distance between the two points is $d=8.6m$

The polar coordinate of A is $\left(4.47,296.57\right)$

The polar coordinate of B is $\left(4.24,135\right)$

Explanation:

The two points are $A(2,-4)$ and $B(-3,3)$

The distance between two points is given by,

$d=\sqrt{(2+3)^{2}+(-4-3)^{2}}\\d=\sqrt{(5)^{2}+(-7)^{2}}\\d=\sqrt{25+49}\\d=8.6$

Thus, the distance between the two points is $d=8.6m$

The polar coordinates of A can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $A(2,-4)$ , we get,

Distance = $\sqrt{2^{2} +(-4)^{2} }=\sqrt{4+16 }=4.47$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{-4}{2}=-63.43$

To make the angle positive, let us add 360,

$\theta=360-63.43=296.57$

The polar coordinate of A is $\left(4.47,296.57\right)$

Similarly, The polar coordinate of B can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $B(-3,3)$ , we get,

Distance = $\sqrt{(3)^{2}+(3)^{2}}=4.24$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{3}{-3}=-45$

To make the angle positive, let us add 360,

$\theta=180-45=135^{\circ}$

The polar coordinate of B is $\left(4.24,135\right)$

5 0

3 years ago