Answer:
x = 4, TU = 22
Step-by-step explanation:
Given that TS bisects TU at Q , then
TQ = QU , substitute values
5x - 9 = 15 - x ( add x to both sides )
6x - 9 = 15 ( add 9 to both sides )
6x = 24 ( divide both sides by 6 )
x = 4
Thus
TU = 5x - 9 + 15 - x = 4x + 6 = 4(4) + 6 = 16 + 6 = 22
Answer:
From the said lesson, the difficulty that I have been trough in dealing over the exponential expressions is the confusion that frequently occurs across my system whenever there's a thing that I haven't fully understand. It's not that I did not actually understand what the topic was, but it is just somewhat confusing and such. Also, upon working with exponential expressions — indeed, I have to remember the rules that pertain to dealing with exponents and frequently, I will just found myself unconsciously forgetting what those rule were — rules which is a big deal or a big thing in the said lesson because it is obviously necessary/needed over that matter. Surely, it is also a big help for me to deal with exponential expressions since it's so much necessary — it's so much necessary but I keep fogetting it.. hence, that's why I call it a difficulty. That's what my difficulty. And in order to overcome that difficulty, I will do my best to remember and understand well the said rules as soon as possible.
Answer:
Step-by-step explanation:
Divide both sides by 5.3 and you get d = 8. You can use a calculator for this or just do division by hand.
Lets make it an improper fraction
5/3
we do not know how many chains so we'll put the (x)
therefore
5/3x=9.00
x= 5.4
Answer:
32 i think
Step-by-step explanation:
