Answer:
x=145
Step-by-step explanation:
x+10+x=720-460
Answer:
C. 271.44 ![mm^3](https://tex.z-dn.net/?f=mm%5E3)
Step-by-step explanation:
We need to first find the volume of the pipe, then find the volume of the hole and then subtract the volume of the hole from the volume of the pipe.
The diameter of the pipe is 8.4 mm. This means its radius is:
8.4/2 = 4.2 mm
The height of the pipe is 10 mm
The volume of a cylinder is given as:
![V = \pi r^2h](https://tex.z-dn.net/?f=V%20%3D%20%5Cpi%20r%5E2h)
where r = radius
h - height
Therefore, the volume of the cylinder without the hole is:
![V = \pi * 4.2^2 * 10\\\\V = 554.18 mm^3](https://tex.z-dn.net/?f=V%20%3D%20%5Cpi%20%2A%204.2%5E2%20%2A%2010%5C%5C%5C%5CV%20%3D%20554.18%20mm%5E3)
The diameter of the hole is 6 mm. Its radius is:
6/2 = 3 mm
The volume of the hole is:
![V = \pi * 3^2 * 10\\\\V = 282.74 mm^3](https://tex.z-dn.net/?f=V%20%3D%20%5Cpi%20%2A%203%5E2%20%2A%2010%5C%5C%5C%5CV%20%3D%20282.74%20mm%5E3)
The volume is:
554.18 - 282.74 = 271.44 ![mm^3](https://tex.z-dn.net/?f=mm%5E3)
I do believe 10 it should be the answer
Answer:
![27.25\ ft^2](https://tex.z-dn.net/?f=27.25%5C%20ft%5E2)
Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
we know that
The area on the side of the house that is NOT covered by the light is equal to the area of semicircle minus the area covered by a spotlight on the side of a house
Find the area of the semicircle
The area of a semicircle is equal to
![A=\frac{1}{2}\pi r^{2}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5Cpi%20r%5E%7B2%7D)
we have
![r=25\ ft\\\pi=3.14](https://tex.z-dn.net/?f=r%3D25%5C%20ft%5C%5C%5Cpi%3D3.14)
substitute
![A=\frac{1}{2}(3.14)(25)^{2}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%283.14%29%2825%29%5E%7B2%7D)
![A=981.25\ ft^2](https://tex.z-dn.net/?f=A%3D981.25%5C%20ft%5E2)
Find the difference
![A=981.25-954=27.25\ ft^2](https://tex.z-dn.net/?f=A%3D981.25-954%3D27.25%5C%20ft%5E2)