3 years ago

Points (-5,-3) (-2,-2) (-4,-6) reflected over y=-x-1

Mathematics

1 answer:

Mars2501 [29]3 years ago

8 0

Answer:

frfrfr

Step-by-step explanation:

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tresset_1 [31]

The given inequality is:

$|-8x+24| \leq 16$

This inequality can be divided in two parts as:

a) $-16 \leq -8x +24$
b) $-8x + 24 \leq 16$

Solving part a:

$-16 \leq -8x+24 \\ \\ 
-40 \leq -8x \\ \\ 
5 \geq x \\ 
or \\ 
x \leq 5$

Solving part b:

$-8x+24 \leq 16 \\ \\ 
-8x \leq -8 \\ \\ 
x \geq 1$

Therefore, the solution to the given inequality is $x \leq 5$ and $x \geq 1$ . Combining both the ranges we get the solution: $1 \leq x \leq 5$ .

In interval notation, this solution can be expressed as [1,5]

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aivan3 [116]

a. This is an equation because it has to parts, separated by an equal sign

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