What is the sum of the infinite series: 1-4+16-64+. . .

Mathematics

1 answer:

Andrei [34K]3 years ago

5 0

Step-by-step explanation:

I think we cannot find the sum because it will continue on so the series is multiply by 4

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In Texas the state sales

Leto [7]

Answer: $826.8

Step-by-step explanation:

First, we add the amount of money that the machines sold for:

$420 + $360 = $780

Next, we multiply it by the sales tax, 6%,

$780 x 6%(0.06) = $46.80

Finally, we add this to the total:

$780 + $46.80 = $826.80

Alternatively, you can add the total sales and multiply by 106% using the 2-step method.

4 0

3 years ago

Read 2 more answers

Sveta_85 [38]

Answer:

i think its 6 may be wrong

4 0

3 years ago

Find the interval(s) where the function is increasing and the interval(s) where it is decreasing. (Enter your answers using inte

Mashcka [7]

Answer:

f'(x) > 0 on $(-\infty ,\frac{1}{e})$ and f'(x)<0 on $(\frac{1}{e},\infty)$

Step-by-step explanation:

1) To find and interval where any given function is increasing, the first derivative of its function must be greater than zero:

$f'(x)>0$

To find its decreasing interval :

$f'(x)$

2) Then let's find the critical point of this function:

$f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}[6-2^{2x}]=\frac{\mathrm{d} }{\mathrm{d}x}[6]-\frac{\mathrm{d}}{\mathrm{d}x}[2^{2x}]=0-[ln(2)*2^{2x}*\frac{\mathrm{d}}{\mathrm{d}x}[2x]=-ln(2)*2^{2x}*2=-ln2*2^{2x+1\Rightarrow }f'(x)=-ln(2)*2^{2x}*2\\-ln(2)*2^{2x+1}=-2x^{2x}(ln(x)+1)=0$

2.2 Solving for x this equation, this will lead us to one critical point since x' is not defined for Real set, and x'' $=\frac{1}{e}$ ≈0.37 for e≈2.72