Answer: the following are required for IV-3 to have condition
Explanation:
-II-4 passes an X b chromosome to III-4 (probability = 1/2).
-If III-4 has the genotype X B X b (accounted for by the above probability), then she passes an X b chromosome to IV-3 (probability = 1/2).
-III-5 passes a Y chromosome to IV-3 (probability = 1/2).
All of these requirements are needed in sequence, so you apply the product rule here, too (1/2 x 1/2 x 1/2 = 1/8).
Once the individual probabilities are known, the sum and/or product rules can be used for various combinations (both conditions, either condition, etc.).
No real solutions, because for all real numbers the square of number is greater or equal 0.
Answer:
a.(-b) ( third choice)
explanation:
-a+b - there is no plus sign for -a.b.
not -a+b
(-a)(-6)=6a (-negative sign and -negative sign=+positive sign)
Be more specific, what your talking about ?
