Answer:
what is the rest of the question?
Step-by-step explanation:
The answer is a.0.32 km.
The speed that a tsunami can travel is modeled by the equation is s = 356√d.
It is given:
s = 200 km/h
d = ?
Now, let's substitute s in the equation and find d:
s = 356√d
200 = 356√d
√d = 200 ÷ 356
√d = 0.562
Now, let's square both sides of the equation:
(√d)² = (0.562)²
d = (0.562)² = 0.316 ≈ 0.32
Therefore, <span> the approximate depth (d) of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.</span>
Wouldn’t it be 4^P
i light be wrong
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Step-by-step explanation:
(x + 12)(x - 6)
x2 - 6x + 12x - 72
x2 + 6x - 72
