$\sin^{2} \theta+\cos^{2} \theta=1 \\ \\ \sin^{2} \theta+\left(\frac{\sqrt{3}}{3} \right)^{2}=1 \\ \\ \sin^{2} \theta+\frac{1}{3}=1 \\ \\ \sin^{2} \theta=\frac{2}{3} \\ \\ \theta=-\frac{\sqrt{2}}{\sqrt{3}}=\boxed{-\frac{\sqrt{6}}{3}}$

5 0

2 years ago

2x+5<9 solve that please!

sesenic [268]

Answer:

Step-by-step explanation:

2x+5<9

= 2x<9-5

= 2x<4

*divide both sides by 2

= x<2

7 0

3 years ago

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Which expression represents the sum of ( 2x-5y) and (x+y)?

nekit [7.7K]

Sum of ( 2x-5y) and (x+y)?
=2x-5y+x+y
=3x-4y

6 0

4 years ago

the point slope form of the equation of a line that passes through (8,4) and (0,2) is y-4=1/4(×-8) what is the slope intercept f

marissa [1.9K]

Answer:

$\large\boxed{y=\dfrac{1}{4}x+2}$

Step-by-step explanation:

The slope-intercept form of the equation of a line:

$y=mx+b$

m - slope

b - y-intercept → (0, b)

The point-slope form of the equation of a line:

$y-y_1=m(x-x_1)$

m - slope

(x₁, y₁) - point

We have the equation of a line:

$y-4=\dfrac{1}{4}(x-8)\to m=\dfrac{1}{4}$

and the point (0, 2) → b = 2.

Substitute:

$y=\dfrac{1}{4}x+2$

7 0

3 years ago

Read 2 more answers