X + 3y = 7
x = -3y + 7

2x + 4y = 8
2(-3y + 7) + 4y = 8
-6y + 14 + 4y = 8
-2y = 8 - 14
-2y = - 6
y = -6/-2
y = 3

x + 3y = 7
x + 3(3) = 7
x + 9 = 7
x = 7 - 9
x = -2

solution is (-2,3)

6 0

3 years ago

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A box of 42 chocolates contains milk and dark chocolates in the ratio of 3:4. How many chocolates of each type there are?

Elza [17]

<h2>Answer:The number of milk chocolates are 18 and the number of dark chocolates are 24.</h2>

Step-by-step explanation:

Let the number of milk chocolates be $m$ .

Let the number of dark chocolates be $d$ .

Given that the box contains the milk and dark chocolates in the ratio $3:4$ .

So, $\frac{m}{d}=\frac{3}{4}$ ...(i)

Given that the total number of chocolates are $42$ .

So, $m+d=42$ . ...(ii)

Using (i) and (ii),

$m+\frac{4}{3}m=42$

$\frac{7}{3}m=42$

$m=18$

$d=\frac{4}{3}m=\frac{4}{3}\times 18=24$

So,the number of milk chocolates are $18$ and the number of dark chocolates are $24$ .

4 0

3 years ago