Answer:
P'(-6,-4)
Step-by-step explanation:
By translating the point under the translation, to put it into a simpler form, it says to move the point 4 units to the left and 6 units down. Using this, the point will move to P'(-6,-4)
Answer:
3
Step-by-step explanation:
2(x + 1) = 3(5 - x) + 2
Distribute,
2(x + 1) = 3(5 - x) + 2
2x + 2 = 3(5 - x) + 2
Rearrange terms,
2x + 2 = 3(5 - x) + 2
2x + 2 = 3(-x + 5) + 2
Distribute,
2x + 2 = 3(-x + 5) + 2
2x + 2 = -3x + 15 + 2
Add the numbers,
2x + 2 = -3x + 15 + 2
2x + 2 = -3x + 17
Subtract 2 from both sides,
2x + 2 = -3x + 17
2x + 2 - 2 = -3x + 17 - 2
2x = -3x + 17 - 2
2x = -3x + 15
Add 3x to both sides,
2x = -3x + 15
2x + 3x = -3x + 3x + 15
5x = -3x + 3x + 15
5x = 15
Divide both sides by the same factor (15),
5x = 15
5x/5 = 15/5
x = 15/5
x = 3
Hence, the answer is 3.
Answer:
There is no statistical evidence at 1% level to accept that the mean net contents exceeds 12 oz.
Step-by-step explanation:
Given that a random sample of ten containers is selected, and the net contents (oz) are as follows: 12.03, 12.01, 12.04, 12.02, 12.05, 11.98, 11.96, 12.02, 12.05, and 11.99.
We find mean = 11.015
Sample std deviation = 3.157
a) 
(Right tailed test)
Mean difference /std error = test statistic
p value =0.174
Since p >0.01, our alpha, fail to reject H0
Conclusion:
There is no statistical evidence at 1% level to accept that the mean net contents exceeds 12 oz.
You can graph this two ways. You can change it into slope intercept form, y=mx+b, or find the x- and y-intercepts. To change it to slope intercept form you would need to add 12x to both sides and divide both sides by 18. By doing this, you'd get y=2/3x+17/9. You'd then go up on the y-axis to 17/9 or 1.89 and place a point. You'd then go up two and to the right three and place another point. You can do this one more time and connect the points. To find the x- and y- intercepts you would plug 0 in for x and solve for y, getting 17/9, and plug 0 in for y and solve for x, getting -17/6. You'd then plot the points (-17/6, 0) and (17/9) and connect the points forming a line.
