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Naya [18.7K]
3 years ago
12

Where does the point (6,2) lie on a circle centered at (7,8) with a radius of 6

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
5 0

Answer:

<em>The point lies barely outside of the circle</em>

Step-by-step explanation:

<u>Equation of a Circle</u>

Given its center (h,k) and radius r, the equation of a circle is given by

(x-h)^2+(y-k)^2=r^2

The circle given in the question is centered at (7,8) and has a radius of 6, thus its equation is

(x-7)^2+(y-8)^2=6^2

(x-7)^2+(y-8)^2=36

To find out if a point (a,b) is outside or inside the circle area, the following conditions apply.

if (a-7)^2+(b-8)^2>36 then the point lies outside of the circle area

if (a-7)^2+(b-8)^2 then the point lies inside of the circle area

Let's use the point as given (6,2)

(6-7)^2+(2-8)^2=1+36=37

Thus the point lies barely outside of the circle

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