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BlackZzzverrR [31]
4 years ago
13

Simplify by using radical. Rationalize denominators.

la1" title=" 2a^{-1/2} " alt=" 2a^{-1/2} " align="absmiddle" class="latex-formula">
Mathematics
2 answers:
wariber [46]4 years ago
6 0
2a^{- \frac{1}{2} }= \cfrac{2}{a^{ \frac{1}{2} }} = \cfrac{2}{ \sqrt{a} } = \cfrac{2 \sqrt{a} }{a}
Luda [366]4 years ago
5 0

Answer:

\frac{2\sqrt a}{a}

Step-by-step explanation:

The given equation is  2a^{-1/2}

The exponent rule: x^{-a}=\frac{1}{x^a}

Using this rule, we get

2a^{-1/2}\\\\=\frac{2}{a^1/2}

We can rewrite this in radical form as

\frac{2}{\sqrt a}

Rationalize the denominator by multiplying numerator and denominator by \sqrt a

\frac{2}{\sqrt a}\cdot \frac{\sqrt a}{\sqrt a}

On simplifying

\frac{2\sqrt a}{a}

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